我有幾個 URL，因此，每個 URL 都有一個資料結構。網址：
case "Get Day":
return "time/get_day.php"
case "Get Time":
return "time/get_time.php"
case "Get Current Time":
return "user/get_current_time.php"
結構：
struct Day: Codable {
var status: Int? = nil
var error_message: String? = nil
var result: [Result]? = nil
}
struct Time: Codable {
let status: Int?
let error_message: String?
let result: [Result]?
struct Result: Codable {
let id: String
let startTime: String
let endTime: String
}
}
struct CurrentTime: Codable {
let status: Int?
let error_message: String?
let current_time: Int?
}
struct Result: Codable {
let id: String
let name_en: String
let name_ru: String
let name_kk: String
}
目前我有一個 parseJson() 函式。其中我可以手動更改結構型別以進行一一決議。但我想不出如何做到這一點，這樣我就不會手動更改代碼中的任何內容。
func parseJson(data: Data) {
let decoder = JSONDecoder()
do {
let parsedData = try decoder.decode(Day.self, from: data)
print(parsedData)
} catch {
print("Error parsing Json:\(error)")
}
}
請，如果您有示例或想法，請與我分享。
uj5u.com熱心網友回復：
// Generic function to decode any decodable struct
func parseJson<T: Decodable>(data: Data) -> T? {
let decoder = JSONDecoder()
do {
let parsedData = try decoder.decode(T.self, from: data)
return parsedData
} catch {
return nil
}
}
// Usage
let someDay: Day? = parseJson(data: dayData)
let sometime: Time? = parseJson(data: timeData)
轉載請註明出處，本文鏈接：https://www.uj5u.com/gongcheng/337256.html