我需要在下面的陣列中找到具有相同 id 的元素,添加它們的數量并將它們寫在一行中。
let arr = [
{ itemId: 123, name: '0', quantity: 2 },
{ itemId: 1, name: '1', quantity: 2 },
{ itemId: 13, name: '2', quantity: 2 },
{ itemId: 13, name: '3', quantity: 2 },
{ itemId: 13, name: '4', quantity: 24 },
{ itemId: 13, name: '5', quantity: 2 },
{ itemId: 1, name: '6', quantity: 4 },
{ itemId: 1, name: '7', quantity: 2 },];
我想要這樣的輸出:
[{ itemId: 123, name: '1', quantity: 2 },
{ itemId: 1, name: '2', quantity: 6 },
{ itemId: 13, name: '6', quantity: 30 }];
還有我的代碼:
const getPureList = () => {
for (let index = 0; index < arr.length; index ) {
for (let a = index 1; a < arr.length; a ) {
if (arr[index].itemId === arr[a].itemId) {
arr[index].quantity = arr[a].quantity;
arr.splice(a, 1);
}
}
}
return arr;
};
謝謝你的幫助。
uj5u.com熱心網友回復:
通過將nameod保留為組的第一個物件,您可以將一個物件用于分組并將值作為結果。
const
array = [{ itemId: 123, name: '0', quantity: 2 }, { itemId: 1, name: '1', quantity: 2 }, { itemId: 13, name: '2', quantity: 2 }, { itemId: 13, name: '3', quantity: 2 }, { itemId: 13, name: '4', quantity: 24 }, { itemId: 13, name: '5', quantity: 2 }, { itemId: 1, name: '6', quantity: 4 }, { itemId: 1, name: '7', quantity: 2 }],
result = Object.values(array.reduce((r, o) => {
r[o.itemId] ??= { ...o, quantity: 0 };
r[o.itemId].quantity = o.quantity;
return r;
}, {}));
console.log(result);
.as-console-wrapper { max-height: 100% !important; top: 0; }
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標籤:javascript 算法
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