我在 MongoDB 中有一個包含檔案的集合:
[
{
"_id" : ObjectId("61ba65af74cf385ee93ad2c7"),
"Car_brand":"BMW X7",
"Plate_number":"8OP66",
"Model_year":"2018",
"Company":"BMW",
"Purchase_year":"2019",
"Body_color":"red",
"Mileage":1000,
"Price":35000,
"Body_type":"crossover"
},
{
"_id" : ObjectId("61ba65af74cf385ee93ad2c8"),
"Car_brand":"Tesla Model X",
"Plate_number":"5XR56",
"Model_year":"2015",
"Company":"Tesla Motors",
"Purchase_year":"2019",
"Body_color":"white",
"Mileage":800,
"Price":25000,
"Body_type":"SUV"
},
{
"_id" : ObjectId("61ba65af74cf385ee93ad2c9"),
"Car_brand":"Tesla Cybertruck",
"Plate_number":"2ED45",
"Model_year":"2021",
"Company":"Tesla Motors",
"Purchase_year":"2021",
"Body_color":"gray",
"Mileage":0,
"Price":50000,
"Body_type":"pickup"
},
{
"_id" : ObjectId("61ba65af74cf385ee93ad2ca"),
"Car_brand":"Lamborghini Aventador",
"Plate_number":"2MN50",
"Model_year":"2011",
"Company":"Lamborghini",
"Purchase_year":"2017",
"Body_color":"orange",
"Mileage":700,
"Price":45000,
"Body_type":"supercar"
},
{
"_id" : ObjectId("61ba65af74cf385ee93ad2cb"),
"Car_brand":"BMW X7",
"Plate_number":"3QW14",
"Model_year":"2018",
"Company":"BMW",
"Purchase_year":"2020",
"Body_color":"black",
"Mileage":4500,
"Price":14000,
"Body_type":"crossover"
},
{
"_id" : ObjectId("61ba65af74cf385ee93ad2cc"),
"Car_brand":"Mercedes-Benz G-Class",
"Plate_number":"9KI24",
"Model_year":"2017",
"Company":"Mercedes-Benz",
"Purchase_year":"2017",
"Body_color":"black",
"Mileage":6000,
"Price":13000,
"Body_type":"SUV"
},
{
"_id" : ObjectId("61ba65af74cf385ee93ad2cd"),
"Car_brand":"BMW X6",
"Plate_number":"2GH47",
"Model_year":"2008",
"Company":"BMW",
"Purchase_year":"2016",
"Body_color":"white",
"Mileage":4500,
"Price":14500,
"Body_type":"SUV"
},
{
"_id" : ObjectId("61ba65af74cf385ee93ad2ce"),
"Car_brand":"Chevrolet Camaro",
"Plate_number":"7BV58",
"Model_year":"2015",
"Company":"Chevrolet",
"Purchase_year":"2020",
"Body_color":"orange",
"Mileage":4000,
"Price":43000,
"Body_type":"cabriolet"
},
{
"_id" : ObjectId("61ba65af74cf385ee93ad2cf"),
"Car_brand":"Ford Mustang",
"Plate_number":"4AM23",
"Model_year":"2016",
"Company":"Ford Motor Company",
"Purchase_year":"2019",
"Body_color":"purple",
"Mileage":2000,
"Price":30000,
"Body_type":"cabriolet"
},
{
"_id" : ObjectId("61ba65af74cf385ee93ad2d0"),
"Car_brand":"Dodge Challenger",
"Plate_number":"6DL73",
"Model_year":"2020",
"Company":"Dodge (Chrysler Corporation)",
"Purchase_year":"2020",
"Body_color":"red",
"Mileage":0,
"Price":40000,
"Body_type":"muscle car"
}
]
我需要得到:
- 每種體型的顏色數。
- 該公司擁有兩個汽車品牌。
我試過第一個這樣的:
db.Vehicles.aggregate([{$group:{"_id":"$Body_type","Количество цветов":{$sum: 1}}}]);
但我得到了所有的顏色,包括那些重復兩次的顏色。我需要獲得許多不同的顏色。
我想不出對第二個的任何建議。
謝謝。
uj5u.com熱心網友回復:
每種體型的顏色數量
你可以這樣做:
db.collection.aggregate([
{
"$group": {
"_id": "$Body_type",
"colors_array": {
"$addToSet": "$Body_color"
}
}
},
{
"$project": {
"colors_number": {
"$size": "$colors_array"
},
"colors_array": 1
}
}
])
請注意,我還包含了所有顏色的陣列 -colors_array屬性。如果您只需要唯一顏色的數量,而不需要另外的顏色陣列,則只需更改"colors_array": 1為"colors_array": -1.
作業示例
該公司擁有兩個汽車品牌。
你可以這樣做:
db.collection.aggregate([
{
"$group": {
"_id": "$Company",
"brands_array": {
"$addToSet": "$Car_brand"
}
}
},
{
"$set": {
"brands_number": {
"$size": "$brands_array"
}
}
},
{
"$match": {
"brands_number": 2
}
}
])
作業示例
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