將某些資料從一個物件抓取到另一個物件

我的目標是從資料庫中獲取某些值到 curated_database 中，但是我基本上堅持將多個專案添加到一個物件中。

var curated_database = {};

var database = {
    0: [{name: 'Micheal'}, 
        {age: 45},
        {education: 'BA'},  
        {income: 245000},  
        {occupation: 'director'}],
    1: [{name: 'John'}, 
        {age: 23},
        {education: 'BA'},  
        {income: 60000},  
        {occupation: 'manager'}],
    2: [{name: 'Judith'}, 
        {age: 45},
        {education: 'PhD'},  
        {income: 140000},  
        {occupation: 'professor'}],
    3: [{name: 'Gill'}, 
        {age: 28},
        {education: 'MS'},  
        {income: 98000},  
        {occupation: 'scientist'}],
    4: [{name: 'Dave'}, 
        {age: 17},
        {education: 'HS'},  
        {income: 30000},  
        {occupation: 'retail associate'}]
};

目標是從較大的物件中獲取類似的某些資訊

curated_database = { 
0 : ['Micheal',245000,'director'],
1: ['John',245000,'manager'],
2: ['Judith',140000,'professor'],
3: ['Gill',98000,'scientist'],
4: ['Dave',30000,'retail associate']
};

我的嘗試

for(data in database){
    desired_contents = [0,3,4]
    for(contents in desired_contents){
    console.log(database[data][desired_contents[contents]]);
    }
    var k = database[data][0];
    if (!currated_database[k.key]) {
        currated_database[k.key] = [];
    }
        currated_database[k.key].push(k.val);
}

uj5u.com熱心網友回復：

你可以通過這種方式實作它：

var curated_database = {};

var database = {
    0: [{name: 'Micheal'},
        {age: 45},
        {education: 'BA'},
        {income: 245000},
        {occupation: 'director'}],
    1: [{name: 'John'},
        {age: 23},
        {education: 'BA'},
        {income: 60000},
        {occupation: 'manager'}],
    2: [{name: 'Judith'},
        {age: 45},
        {education: 'PhD'},
        {income: 140000},
        {occupation: 'professor'}],
    3: [{name: 'Gill'},
        {age: 28},
        {education: 'MS'},
        {income: 98000},
        {occupation: 'scientist'}],
    4: [{name: 'Dave'},
        {age: 17},
        {education: 'HS'},
        {income: 30000},
        {occupation: 'retail associate'}]
};



var indexToExtract = new Set([0,3,4]);

    var wantedLst = Object.values(database)
    .map(lst => lst.filter((ob, idx) => indexToExtract.has(idx)))
    .map((lst, idx) => curated_database[idx] = lst.map(ob => Object.values(ob)[0]))
    
    console.log(curated_database);

uj5u.com熱心網友回復：

使用Array.prototype.map()，Object.keys()和 Object.values()

var curated_database = {};

var database = {
    0: [{name: 'Micheal'}, 
        {age: 45},
        {education: 'BA'},  
        {income: 245000},  
        {occupation: 'director'}],
    1: [{name: 'John'}, 
        {age: 23},
        {education: 'BA'},  
        {income: 60000},  
        {occupation: 'manager'}],
    2: [{name: 'Judith'}, 
        {age: 45},
        {education: 'PhD'},  
        {income: 140000},  
        {occupation: 'professor'}],
    3: [{name: 'Gill'}, 
        {age: 28},
        {education: 'MS'},  
        {income: 98000},  
        {occupation: 'scientist'}],
    4: [{name: 'Dave'}, 
        {age: 17},
        {education: 'HS'},  
        {income: 30000},  
        {occupation: 'retail associate'}]
};

Object.keys(database).map((el)=>{
    var desired_contents = [0,3,4];
    curated_database[el] = [];
    for(var contents in desired_contents){
        curated_database[el].push((Object.values(database[el][desired_contents[contents]]))[0]);
  }
  return;
})

console.log(curated_database);

對您的嘗試進行一些調整

var curated_database = {};

var database = {
    0: [{name: 'Micheal'}, 
        {age: 45},
        {education: 'BA'},  
        {income: 245000},  
        {occupation: 'director'}],
    1: [{name: 'John'}, 
        {age: 23},
        {education: 'BA'},  
        {income: 60000},  
        {occupation: 'manager'}],
    2: [{name: 'Judith'}, 
        {age: 45},
        {education: 'PhD'},  
        {income: 140000},  
        {occupation: 'professor'}],
    3: [{name: 'Gill'}, 
        {age: 28},
        {education: 'MS'},  
        {income: 98000},  
        {occupation: 'scientist'}],
    4: [{name: 'Dave'}, 
        {age: 17},
        {education: 'HS'},  
        {income: 30000},  
        {occupation: 'retail associate'}]
};

for(var data in database){
    desired_contents = [0,3,4]
        if (!curated_database[data]){
        curated_database[data]=[];
    }
    for(var contents in desired_contents){
      curated_database[data].push(Object.values(database[data][desired_contents[contents]])[0]);
    }
}

console.log(curated_database);

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