我需要獲取串列中每個元素的 href，我該怎么做？在 bs4 上
<div class="group">
<a href="link1" target="_blank" rel="rel" class="class">
<h1>"test"</h1>
</a>
<a href="link2" target="_blank" rel="rel" class="class">
<h1>"test2"</h1>
</a>
<a href="link3" target="_blank" rel="rel" class="class">
<h1>"test3"</h1>
</a> </div>
uj5u.com熱心網友回復：
選擇<div>with 類組并迭代其<a>例如 withcss selectors和list comprehension：
[x['href'] for x in soup.select('div.group a')]
例子
from bs4 import BeautifulSoup
html = '''
<div >
<a href="link1" target="_blank" rel="rel" >
<h1>"test"</h1>
</a>
<a href="link2" target="_blank" rel="rel" >
<h1>"test2"</h1>
</a>
<a href="link3" target="_blank" rel="rel" >
<h1>"test3"</h1>
</a>
</div>
'''
soup = BeautifulSoup(html)
[x['href'] for x in soup.select('div.group a')]
輸出
['link1', 'link2', 'link3']
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