將當前日期時間與包括分鐘在內的時間進行比較

將當前日期時間與包括分鐘的時間進行比較的最佳方法是什么。我目前的方法似乎不是最簡潔的。我想在下午 6:30 之后執行一個陳述句。

from datetime import datetime as dt

if (dt.now().hour == 18 and dt.now().minute > 30) or dt.now().hour >= 19:
    print('hello world')

如果我想在下午 6 點 30 分之后和晚上 9 點 30 分之前做，那就更麻煩了。

uj5u.com熱心網友回復：

我會這樣做：

from datetime import datetime

def check_time(date, hour, minute):
    if date > date.replace(hour=hour, minute=minute):
        print('its more than '   str(hour)   ':'   str(minute))
    else:
        print('its less than '   str(hour)   ':'   str(minute))

today = datetime.now()
check_time(today, 18, 30)

uj5u.com熱心網友回復：

您可以使用我為我的一個專案構建的這個功能。我在天、小時、分鐘、秒級別構建了這個功能。我已經根據您的需要減少了它。

def compare_hours(constraint: dict) -> bool:
    from datetime import datetime
    """
    This is used to compare a given hours,minutes against current time
    The constraint must contain a single key and value.
    Accepted keys are: 
        1. before:
            eg {"before": "17:30"}
        2. after:
            eg: {"after": "17:30"}
        3. between:
            eg: {"between": "17:30, 18:30"}
        4. equal:
            eg: {"equal": "15:30"}

    Parameters
    ----------
    constraint : dict
        A dictionary with keys like before, after, between and equal with their corresponding values.

    Returns
    -------
    True if constraint matches else False

    """
    accepted_keys = ("before", "after", "between", "equal")
    assert isinstance(constraint, dict), "Constraint must be a dict object"
    assert len(constraint.keys()) == 1, "Constraint contains 0 or more than 1 keys, only 1 is allowed"
    assert list(constraint.keys())[0] in accepted_keys, f"Invalid key provided. Accepted keys are {accepted_keys}"
    key = list(constraint.keys())[0]
    time_split = lambda x: list(map(int, x.split(":")))
    try:
        if key == "before":
            hours, minutes = time_split(constraint.get(key))
            dt = datetime.now()
            if dt < dt.replace(hour=hours, minute=minutes):
                return True
            return False
        elif key == "after":
            hours, minutes = time_split(constraint.get(key))
            dt = datetime.now()
            if dt > dt.replace(hour=hours, minute=minutes):
                return True
            return False
        elif key == "between":
            dt = datetime.now()
            values = constraint.get(key).replace(' ', '').split(",")
            assert len(values) == 2, "Invalid set of constraints given for between comparison"
            hours, minutes = time_split(values[0])
            dt1 = dt.replace(hour=hours, minute=minutes)
            hours, minutes = time_split(values[1])
            dt2 = dt.replace(hour=hours, minute=minutes)
            assert dt2 > dt1, "The 1st item in between must be smaller than second item"
            if dt > dt1 and dt < dt2:
                return True
            return False
        else:
            hours, minutes = time_split(constraint.get(key))
            dt = datetime.now()
            if dt == dt.replace(hour=hours, minute=minutes):
                return True
            return False
    except Exception as e:
        print(e)

您可以根據需要重復使用該功能。例如：

if compare_hours({"before": "21:00"}) and compre_hours({"after": "18:30"}):
    "do something"

這與使用“between”選項基本相同。

uj5u.com熱心網友回復：

您可以簡單地time從您的物件中提取一個物件datetime并進行直接比較。

>>> from datetime import time, datetime as dt
>>> dt.now()
datetime.datetime(2022, 3, 8, 15, 0, 56, 393436)
>>> dt.now().time() > time(14, 30)
True
>>> dt.now().time() > time(15, 30)
False

標籤：Python python-3.x 约会时间 蟒蛇日期时间

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