按最近的時間順序列印回圈的結果

如何按時間順序對兩個回圈的結果進行排序？它們是兩個不同的回圈，但我想通過混合第一個回圈和第二個回圈來將它們排序在一起，以便及時對所有內容進行排序。基本上，這段代碼會抓取一些新聞的時間和標題，并將它們列印在文本框中。它們是兩個不同的回圈。

我寫了這段代碼，但它不起作用

from datetime import datetime
allnews = news1, news2
allnews.sort()

我沒有錯誤，但我得到了這個輸出，例如：

14.24 TEXAS RANGER #this is loop n.1
14.01 TEXAS RANGER #this is loop n.1
14.20 DETROIT #this is loop n.2
14.13 DETROIT #this is loop n.2

I want to get:
14.24 TEXAS RANGER 
14.20 DETROIT
14.13 DETROIT
14.01 TEXAS RANGER

這是我的代碼中對解決問題有用的部分。我沒有粘貼整個代碼，但我只粘貼了我列印的部分

#textbox
textbox = tk.Listbox(window, width=80, height=20, font=('helvetic', 12), selectbackground="#960000", selectforeground="white", bg="white")
textbox.place(x=1, y=1)

def titoli():

   #code of scraping....

    #TEXAS RANGER
    site_texasrangers = requests.get('....')
    soup = BeautifulSoup(site_texasrangers.content, 'html.parser')
    news = soup.find_all('div', attrs={"class": "tcc-list-news"})

    for each in news:
        for div in each.find_all("div"):
            time= (div.find('span', attrs={'class': 'hh serif'}).text)
            tile=(" ".join([span.text for span in div.select("a > span")]))

            news1 = (f" {time} {'TEXAS RANGER'}, {title}")            
            textbox.insert(tk.END, news1)


    #DETROIT TIGERS
    site_detroit = requests.get('.....')
    soup = BeautifulSoup(site_detroit.content, 'html.parser')
    news = soup.find_all('div', attrs={"class": "tcc-list-news"})

    for each in news:
        for div in each.find_all("div"):
            time= (div.find('span', attrs={'class': 'hh serif'}).text)
            title=(" ".join([span.text for span in div.select("a > span")]))

            news2 = (f" {time} {'DETROIT'}, {title}")       
            textbox.insert(tk.END, news2)


    #sorted
    from datetime import datetime

    allnews = news1, news2
    allnews.sort()


titoli()
window.mainloop()

uj5u.com熱心網友回復：

你做錯了順序。首先，您必須創建空串列，接下來在回圈中您必須將新聞附加到此串列（不顯示），在回圈之后您必須對串列進行排序（使用reverse=True），然后使用回圈將值添加到textbox

像這樣的東西

def titoli():

    # --- before loops ---
    
    allnews = []

    # --- loops ---
    
    #TEXAS RANGER
    site_texasrangers = requests.get('....')
    soup = BeautifulSoup(site_texasrangers.content, 'html.parser')
    news = soup.find_all('div', attrs={"class": "tcc-list-news"})

    for each in news:
        for div in each.find_all("div"):
            time  = div.find('span', attrs={'class': 'hh serif'}).text
            title = " ".join([span.text for span in div.select("a > span")])

            news = f" {time} {'TEXAS RANGER'}, {title})"            

            allnews.append(news)  # <-- append to list without displaying

    #DETROIT TIGERS
    site_detroit = requests.get('.....')
    soup = BeautifulSoup(site_detroit.content, 'html.parser')
    news = soup.find_all('div', attrs={"class": "tcc-list-news"})

    for each in news:
        for div in each.find_all("div"):
            time  = div.find('span', attrs={'class': 'hh serif'}).text
            title = " ".join([span.text for span in div.select("a > span")])

            news = f" {time} {'DETROIT'}, {title})"            

            allnews.append(news)  # <-- append to list without displaying

    # --- after loops --- 

    allnews.sort(reverse=True)

    for news in allnews:
        textbox.insert(tk.END, news)

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