我希望使用 getopts 從同一個引數中獲取多個值。我想使用此腳本對通過檔案提供的主機串列進行 ssh 和運行命令。
用法：.\ssh.sh -f file_of_hosts.txt -c "Command1" "command2"
預期輸出：
ssh userid@server1:command1
ssh userid@server1:command2
ssh userid@server2:commnand1
ssh userid@server2:commnand2
我使用但未能獲得預期結果的示例代碼
id="rm08397"
while getopts ":i:d:s:f:" opt
do
case $opt in
f ) file=$OPTARG;;
c ) cmd=$OPTARG;;
esac
done
shift "$(($OPTIND -1))"
# serv=$(for host in `cat $file`
# do
# echo -e "$host#"
# done
# )
# for names in $serv
# do
# ssh $id@$serv:
for hosts in $file;do
for cmds in $cmd;do
o1=$id@$hosts $cmds
echo $o1
done
done
uj5u.com熱心網友回復：
您可以通過重復來達到效果-c：
declare -a cmds
id="rm08397"
while getopts ":c:f:" opt
do
case $opt in
f ) file="$OPTARG";;
c ) cmds =("$OPTARG");;
esac
done
shift $((OPTIND -1))
for host in $(<$file);do
for cmd in "${cmds[@]}";do
echo ssh "$id@$host" "$cmd"
done
done
# Usage: ./ssh.sh -f file_of_hosts.txt -c "Command1" -c "command2"
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