我正在嘗試在我的網站內建立一個身份驗證系統。我正在向我的 ASP.NET 服務器發送一個包含電子郵件和密碼的簡單 POST 請求，由于某種原因，服務器內的資料（電子郵件和密碼）為空。我不知道自己做錯了什么，而且我是 ASP.NET 和 Angular 的初學者。
角代碼：（我試圖從一些元素內的文本框中顯示文本，它顯示了正確的文本）
isUserLoggedIn: boolean;
emailAddress: string;
password: string;
constructor(private http: HttpClient, @Inject('BASE_URL') private baseUrl: string) {}
login() {
const headers = {'Content-Type': 'application/json', };
const body = { emailAddress: this.emailAddress.toString, password: this.password.toString };
this.http.post<any>(this.baseUrl "login", body, { headers }).subscribe(result => {
this.isUserLoggedIn = result;
if (this.isUserLoggedIn) console.log("Logged in")
else console.log("Not logged in")
}, error => console.error(error));
}
我的 ASP.NET 控制器：
[HttpPost]
[Route("login")]
public bool LoginUser(string emailAddress, string password)
{
// DOES NOT PRINT ANY VALUE OF EMAIL OR PASSWORD
Console.WriteLine("1: " emailAddress);
Console.WriteLine("2: " password);
SakilaContext context = HttpContext.RequestServices.GetService(typeof(SakilaContext)) as SakilaContext;
return context.LoginUser(emailAddress, password);
}
我在 ASP.NET 服務器中的資料庫代碼：
public bool LoginUser(string emailAddress, string password)
{
bool isUserLoggedIn = false;
List<UserModel> list = new List<UserModel>();
using (MySqlConnection conn = GetConnection())
{
string query = $"SELECT * FROM users WHERE email = '{emailAddress}'";
conn.Open();
MySqlCommand cmd = new MySqlCommand(query, conn);
using (MySqlDataReader reader = cmd.ExecuteReader())
{
while (reader.Read())
{
if (reader.HasRows)
{
string db_password = reader.GetString("password");
if (db_password == password)
{
isUserLoggedIn = true;
}
}
}
}
}
return isUserLoggedIn;
}
uj5u.com熱心網友回復：
創建一個LoginModel類。
public class LoginModel
{
public string EmailAddress { get; set; }
public string Password { get; set; }
}
更改Login方法簽名以通過[FromBody].
[HttpPost]
[Route("login")]
public bool LoginUser([FromBody] LoginModel model)
{
Console.WriteLine(model.EmailAddress);
Console.WriteLine(model.Password);
...
}
對于 Angular，我認為以下部分不正確：
const body = { emailAddress: this.emailAddress.toString, password: this.password.toString };
改成
const body = { emailAddress: this.emailAddress.toString(), password: this.password.toString() };
或者
const body = { emailAddress: this.emailAddress, password: this.password };
邊注：
不要連接 SQL 命令中的值，使用帶有.AddWithValue("@parameter", value). 查看為什么我們總是喜歡在 SQL 陳述句中使用引數？.
string query = $"SELECT * FROM users WHERE email = @emailAddress";
conn.Open();
MySqlCommand cmd = new MySqlCommand(query, conn);
cmd.Parameters.AddWithValue("@emailAddress", emailAddress);
參考
[FromBody]屬性
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