從遞回提取中解開所有承諾

我正在嘗試創建一個回傳給定塊的所有子塊的遞回函式。

對于一些背景資訊，我使用 Notion API 從頁面中獲取所有塊。一個塊可以有一個子塊，這些子塊也可以有一個子塊。這就是為什么我需要一個遞回函式來檢查所有塊。

實際上，我已經成功地從 google appscript 制作了一個遞回函式，如下所示

// recursive function to get all nested blocks in a flattened array format
function getSubBlocks(blockId) {
  const url = `https://api.notion.com/v1/blocks/${blockId}/children?page_size=100`
  let options = {
    "async": true,
    "crossDomain": true,
    "method": "get",
    "headers": {
      "Authorization": `Bearer ${NOTION_API_KEY}`,
      "Notion-Version": "2022-02-22",
      "Content-Type": "application/json"
    }
  };

  var response = JSON.parse(UrlFetchApp.fetch(url, options).getContentText());;
  console.log(response)
  let blocks = response.results

  Utilities.sleep(50)

  // guard clause
  if (blocks.length == 0) {
    return
  }

  blocks = blocks.concat(blocks.map((block) => getSubBlocks(block.id)).flat())
  // get rid of undefined
  blocks = blocks.filter(block => block != undefined)
  return blocks
}

我正在嘗試從 node.js 中創建一個相同的功能，但是我在解開所有塊時遇到了麻煩。下面是遞回函式的node-js版本

import fetch from "node-fetch";

// recursive function to get all nested blocks in a flattened array format
async function getSubBlocks(blockId) {
  const url = `https://api.notion.com/v1/blocks/${blockId}/children?page_size=100`;
  let options = {
    async: true,
    crossDomain: true,
    method: "get",
    headers: {
      Authorization: `Bearer ${NOTION_API_KEY}`,
      "Notion-Version": "2022-02-22",
      "Content-Type": "application/json",
    },
  };

  const response = await fetch(url, options);
  const r = await response.json();
  let blocks = r.results;
  // guard clause ends the function if the array is empty
  if (blocks.length == 0) {
    return;
  }
  // for each block objects, check for children blocks in a recursive manner

  let newBlocks = await blocks
    .map(async (block) => await getSubBlocks(block.id))
    .flat();
  blocks = blocks.concat(newBlocks);

  // get rid of undefined
  blocks = blocks.filter((block) => block != undefined);
  return await blocks;
}

getSubBlocks(testBlock)
  .then((r) => console.log(r))
  .catch((error) => console.log(error));

我知道上面的函式是一個異步函式，所以它總是回傳一個承諾。這就是為什么我試圖用 then 子句解開承諾，但我只解開第一個塊，而來自遞回呼叫的其他塊仍然作為承諾呈現。示例輸出如下：

[
  {
    object: 'block',
    id: 'XXXXXXXXXXXX',
    created_time: '2022-05-28T05:15:00.000Z',
    last_edited_time: '2022-05-28T05:15:00.000Z',
    created_by: { object: 'user', id: 'XXXXXX' },
    last_edited_by: { object: 'user', id: 'XXXXXX' },
    has_children: false,
    archived: false,
    type: 'paragraph',
    paragraph: { rich_text: [Array], color: 'default' }
  },
  {
    object: 'block',
    id: 'XXXXXXXXXXXX',
    created_time: '2022-05-28T05:15:00.000Z',
    last_edited_time: '2022-05-28T05:15:00.000Z',
    created_by: { object: 'user', id: 'XXXXXXXXXXXX' },
    last_edited_by: { object: 'user', id: 'XXXXXXXXXXXX' },
    has_children: false,
    archived: false,
    type: 'paragraph',
    paragraph: { rich_text: [], color: 'default' }
  },
  Promise { <pending> },
  Promise { <pending> },
  Promise { <pending> },

]

有沒有辦法解決這個問題？

從更廣泛的意義上說，在使用遞回和獲取時是否有任何最佳實踐來檢索所有值？

uj5u.com熱心網友回復：

您的getSubBlocks函式不回傳Promise.
此外，您可能希望將方法從map普通for...of回圈更改為簡化代碼并洗掉一些不必要await的 .

試試這種方法：

import fetch from 'node-fetch';

// recursive function to get all nested blocks in a flattened array format
async function getSubBlocks(blockId) {
  const url = `https://api.notion.com/v1/blocks/${blockId}/children?page_size=100`;
  let options = {
    async: true,
    crossDomain: true,
    method: 'get',
    headers: {
      Authorization: `Bearer ${NOTION_API_KEY}`,
      'Notion-Version': '2022-02-22',
      'Content-Type': 'application/json',
    },
  };

  const response = await fetch(url, options);
  const r = await response.json();

  let blocks = r.results;
  // guard clause ends the function if the array is empty
  if (blocks && blocks.length == 0) {
    return undefined;
  }

  // for each block objects, check for children blocks in a recursive manner
  for (const block of blocks) {
      const subBlocks = await getSubBlocks(block.id)
      if (subBlocks) blocks = [...blocks, ...subBlocks]
  }

  return blocks;
}

const res = getSubBlocks(testBlock)

標籤：javascript 节点.js 谷歌应用脚​​本 递归 承诺

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