以下是說明我的問題的偽代碼。當所有任務都完成后，父函式最終必須回傳一個承諾（為了清楚起見，我省略了其他的）。父函式呼叫子函式，一些子函式必須遞回地執行它們的任務，因此，為了清楚起見，我將它們分成了作業函式。如果有更清潔的方法，我很想學習它。
在這個例子中如何最好地處理遞回？
// This function must ultimately return a Promise.
async function parentFunction(uId) {
try {
await childFunction(uId);
return Promise.resolve(uId);
} catch (error) {
console.log(error);
}
}
async function childFunction(uId) {
try {
const done = await workerFunction(uId);
if (done) {
return Promise.resolve(true);
} else {
// There are more files to delete; best way to handle recursion?
}
} catch (error) {
console.log(error);
}
}
async function workerFunction(uId) {
try {
// Query the database, limit to 100 files.
const query = await db.queryFiles().limit(100);
if (query.size == 0) {
// Nothing to delete, we're done!
return Promise.resolve(true);
}
// Perform an atomic (all-or-none) batch delete that can only take 100 files at most.
await db.batchDelete(query);
// Batch delete successfull!
if (query.size < 100) {
// The query was less than 100 files so there can be no more files to delete.
return Promise.resolve(true);
} else {
// There may possibly be more files to delete.
// Return a promise or handle recursion here?
return Promise.resolve(false);
}
} catch (error) {
console.log(error);
}
}
uj5u.com熱心網友回復：
只要做遞回就可以了！
async function deleteFiles() {
const query = await db.queryFiles().limit(100)
if (query.size > 0) {
await db.batchDelete(query)
}
if (query.size === 100) {
return deleteFiles()
}
return true;
}
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標籤：javascript 递归