如何在子類的復制建構式中呼叫父模板類的復制建構式？
// Type your code here, or load an example.
#include<vector>
#include <iostream>
template <typename T>
class Parent {
public:
Parent() {};
const std::vector<T>& getDims() const { return m_dims; };
void setDims(const std::vector<T> dims) { m_dims = dims; };
Parent(const Parent& p) { m_dims = p.getDims(); };
private:
std::vector<T> m_dims;
};
template <typename T>
class Child : public Parent<T> {
public:
Child() {};
const std::vector<T>& getCenter() const { return m_center; };
void setCenter(const std::vector<T> center) { m_center = center; };
Child(const Child& c) {
m_center = c.getCenter();
// How can I trigger the copy constructor of the parent class
// and copy m_dims instead of the following
this->setDims(c.getDims());
}
private:
std::vector<T> m_center;
};
int main(){
Child<int> child1;
child1.setDims({3, 1, 1, 1}); // Parent function
child1.setCenter({1, 2, 3, 4}); // Child function
Child<int> child2 = child1;
return 0;
}
uj5u.com熱心網友回復：
template <typename T>
class Child : public Parent<T> {
public:
Child() {};
Child(const Child& c): Parent<T>(c) {
m_center = c.getCenter();
}
private:
std::vector<T> m_center;
};
你的基類在Parent<T>這里。
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