如何通過php檔案將變數傳遞給bash腳本-有解無憂

我需要從 php 檔案運行一個 bash 腳本。這是我的嘗試...

$old_path = getcwd();
chdir('/home/svradmin/scripts');
$output = shell_exec('./testbash.sh');
chdir($old_path);

我testbash.sh的如下..

#!/bin/bash
echo "Hello World"

這很好用......現在我需要從我的 php 函式中傳遞一個變數，并據此 bash 腳本應該運行.. 舉個例子..

   function fcn1() {
    $old_path = getcwd();
    chdir('/home/svradmin/scripts');
    $output = shell_exec('./testbash.sh');//need to pass variable 'fcn1'
    chdir($old_path);
    }



   function fcn2() {
    $old_path = getcwd();
    chdir('/home/svradmin/scripts');
    $output = shell_exec('./testbash.sh');//need to pass variable 'fcn2'
    chdir($old_path);
    }

所以bash腳本需要改變如下，

     #!/bin/bash
//If variable fcn1 received
    echo "Hello World!! fcn1 has executed.."

//If variable fcn2 received
    echo "Hello World!! fcn2 has executed.."

uj5u.com熱心網友回復：

例子

只需在通話后放置您的變數-

$output = shell_exec('./testbash.sh your_var_1 your_var_2');

然后在你的 bash 腳本中：

#!/bin/bash

var1=$1
var2=$2

echo "Hello World, var 1 is $var1 and var 2 is $var2"

更新

所以你的函式看起來像：

function fcn2() {
    $old_path = getcwd();
    chdir('/home/svradmin/scripts');
    $var = "Hello Hello";
    // Or as Fravadona suggested:
    $var = escapeshellarg("Hello Hello");
    $output = shell_exec("./testbash.sh $var");
    chdir($old_path);
    return $output;
}

function fcn1() {
    $old_path = getcwd();
    chdir('/home/svradmin/scripts');
    $var = "Hello";
    // Or as Fravadona suggested:
    $var = escapeshellarg("Hello");
    $output = shell_exec("./testbash.sh $var");
    chdir($old_path);
    return $output;
}

echo fcn1();
echo fcn2();

還有你的 ..

#!/bin/bash

var=$1

echo "Hello World!! $var has executed.."

uj5u.com熱心網友回復：

備注：要將 PHP 變數的內容傳遞給 shell，您絕對需要對其進行轉義：

$var='fcn1'

$output = shell_exec('./testbash.sh'.' '.escapeshellarg($var));

然后，您可以安全地將其用作引數：

#!/bin/bash
echo "Hello World!! $1 has executed.."

轉載請註明出處，本文鏈接：https://www.uj5u.com/gongcheng/493694.html

標籤：php 重击壳执行

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