如何將PHPcURL格式轉換為GuzzleLaravel格式

目前我正在嘗試測驗一些 API 端點使用郵遞員。正如我們所知，郵遞員為我們提供了將請求集成到許多不同語言的代碼中的資訊。所以我在我的 laravel 框架上選擇代碼格式 PHP-cURL 并且它可以作業。但是我想將 PHP-cURL 格式轉換為 laravel Guzzle。但沒有用。

這是 PHP-cURL 代碼

$curl = curl_init();

curl_setopt_array($curl, array(
  CURLOPT_URL => 'https://sandbox.plaid.com/asset_report/create',
  CURLOPT_RETURNTRANSFER => true,
  CURLOPT_ENCODING => '',
  CURLOPT_MAXREDIRS => 10,
  CURLOPT_TIMEOUT => 0,
  CURLOPT_FOLLOWLOCATION => true,
  CURLOPT_HTTP_VERSION => CURL_HTTP_VERSION_1_1,
  CURLOPT_CUSTOMREQUEST => 'POST',
  CURLOPT_POSTFIELDS =>'{
   "client_id": "xxxx",
   "secret": "xxxx",
   "access_tokens": ["access-sandbox-xxx"],
   "days_requested": 30,
   "options": {
      "client_report_id": "ENTER_CLIENT_REPORT_ID_HERE",
      "webhook": "https://www.example.com/webhook",
      "user": {
        "client_user_id": "ENTER_USER_ID_HERE",
        "first_name": "ENTER_FIRST_NAME_HERE",
        "middle_name": "ENTER_MIDDLE_NAME_HERE",
        "last_name": "ENTER_LAST_NAME_HERE",
        "ssn": "111-22-1234",
        "phone_number": "1-415-867-5309",
        "email": "ENTER_EMAIL_HERE"
      }
   }
 }',
  CURLOPT_HTTPHEADER => array(
    'Content-Type: application/json'
  ),
));

$response = curl_exec($curl);

curl_close($curl);
echo $response;

這種 PHP-cURL 格式可以成功運行并在我的 laravel 上顯示回應。但是當我更改為 Laravel Guzzle 時.. 它顯示錯誤。這是guzzle代碼

use GuzzleHttp\Client;

$guzzle = new Client;
$getAccestToken = $guzzle->request('POST', 'https://sandbox.plaid.com/asset_report/create', [
    'headers' => ['Content-Type' => 'application/json'],
    'json' => [
                "client_id" => "xxx",
                "secret" => "xxx",
                "access_token" => [ "access-sandbox-xxx" ] ,
                "days_requested" => 30,
                "options" => [
                        "client_report_id" => "ENTER_CLIENT_REPORT_ID_HERE",
                        "webhook" => "https://www.example.com/webhook",
                        "user" => [
                                "client_user_id" => "ENTER_USER_ID_HERE",
                                "first_name" => "ENTER_FIRST_NAME_HERE",
                                "middle_name" => "ENTER_MIDDLE_NAME_HERE",
                                "last_name" => "ENTER_LAST_NAME_HERE",
                                "ssn" => "111-22-1234",
                                "phone_number" => "1-415-867-5309",
                                "email" => "ENTER_EMAIL_HERE"
                            ]
                    ]
                ]   
]); 

顯示錯誤

客戶端錯誤：POST https://sandbox.plaid.com/asset_report/create導致400 Bad Request回應：{ "display_message": null, "documentation_url": "https://plaid.com/docs/?ref=error#invalid-request-errors", "error (truncated...)

我的 guzzle 代碼中缺少什么。

請幫忙。

uj5u.com熱心網友回復：

Laravel 有可用的 Http 客戶端，它是 guzzle 的包裝器：

$response = Http::withToken($token)->post('yourUrl', [ params ]);

dd($response->body());

uj5u.com熱心網友回復：

您應該嘗試替換json為body：

此外，將陣列轉換為有效的 JSON 格式。

參考資料：https ://stackoverflow.com/a/39525059/5192105

use GuzzleHttp\Client;

$guzzle = new Client;
$getAccestToken = $guzzle->request('POST', 
'https://sandbox.plaid.com/asset_report/create', [
'headers' => ['Content-Type' => 'application/json'],
'body' => json_encode([
            "client_id" => "xxx",
            "secret" => "xxx",
            "access_token" => [ "access-sandbox-xxx" ] ,
            "days_requested" => 30,
            "options" => [
                    "client_report_id" => "ENTER_CLIENT_REPORT_ID_HERE",
                    "webhook" => "https://www.example.com/webhook",
                    "user" => [
                            "client_user_id" => "ENTER_USER_ID_HERE",
                            "first_name" => "ENTER_FIRST_NAME_HERE",
                            "middle_name" => "ENTER_MIDDLE_NAME_HERE",
                            "last_name" => "ENTER_LAST_NAME_HERE",
                            "ssn" => "111-22-1234",
                            "phone_number" => "1-415-867-5309",
                            "email" => "ENTER_EMAIL_HERE"
                        ]
                ]
            ])   
]); 

uj5u.com熱心網友回復：

我找到了答案。我錯字了

"access_token" => [ "access-sandbox-xxx" ] ,

應該用“令牌”

"access_tokens" => [ "access-sandbox-xxx" ] ,

并且可以正常運行。感謝您的所有回復。

標籤：php拉拉维尔卷曲

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