如何根據時間戳計算并獲得最大完整值之前的進度？
def full_energy():
time_now = 1666650096 #changes every update
time_end = 1666679529
max_energy = 50
diff = datetime.utcfromtimestamp(time_now) - datetime.utcfromtimestamp(time_end)
secs = diff.total_seconds()
???
# expected output
# x/y (z)
# 25/50 (50%)
如何根據此樣本獲取 x 和 z 的值？
uj5u.com熱心網友回復：
像這樣的東西會起作用。您需要提供開始時間來計算完成百分比。不確定您希望顯示幕如何作業：
from datetime import datetime, timedelta
import time
def full_energy(start, now, end):
max_energy = 50
percent = (now - start) / (end - start)
current_energy = max_energy * percent
# In a typical text console this will overwrite the same line
print(f'\r{current_energy:.0f}/{max_energy} ({percent:.0%})', end='', flush=True)
start = datetime.now()
end = start timedelta(seconds=10)
while (now := datetime.now()) <= end:
time.sleep(.2)
full_energy(start, now, end)
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