PTA 7-2 猜數列游戲2-2

在猜數列游戲1的基礎上，按順序回圈提供6個不同的數列，每次按順序給出其中一個數列的連續兩個數，再要求用戶作答，6個數列大小不固定，即每個數列大小不局限于8個數，可能是10個，100個，1000個數：

• 1：Fibonacci:1,1,2,3,5,8,13,21
• 2：Lucas:1,3,4,7,11,18,29,47
• 3：Pell:1,2,5,12,29,70,169,408
• 4：Triangular：1,3,6,10,15,21,28,36
• 5：Square：1,4,9,16,25,36,49,64
• 6：Pentagonal：1,5,12,22,35,51,70,92

輸入格式:

根據提示輸入整數數值或Y或N

輸出格式:

與猜數列游戲1要求一致，

輸入樣例:

在這里給出一組輸入，例如：

2
Y
4
Y
5
Y
6
Y
9
Y
12
Y
3
Y
7
Y
12
Y
10
Y
16
Y
22
Y
5
Y
11
Y
29
N

輸出樣例:

在這里給出相應的輸出，例如：

The first 2 value is 1,1.What is the next value?
Want to try another sequence?(Y/N)
The first 2 value is 1,3.What is the next value?
Want to try another sequence?(Y/N)
The first 2 value is 1,2.What is the next value?
Want to try another sequence?(Y/N)
The first 2 value is 1,3.What is the next value?
Want to try another sequence?(Y/N)
The first 2 value is 1,4.What is the next value?
Want to try another sequence?(Y/N)
The first 2 value is 1,5.What is the next value?
Want to try another sequence?(Y/N)
The first 2 value is 1,2.What is the next value?
Want to try another sequence?(Y/N)
The first 2 value is 3,4.What is the next value?
Want to try another sequence?(Y/N)
The first 2 value is 2,5.What is the next value?
Want to try another sequence?(Y/N)
The first 2 value is 3,6.What is the next value?
Want to try another sequence?(Y/N)
The first 2 value is 4,9.What is the next value?
Want to try another sequence?(Y/N)
The first 2 value is 5,12.What is the next value?
Want to try another sequence?(Y/N)
The first 2 value is 2,3.What is the next value?
Want to try another sequence?(Y/N)
The first 2 value is 4,7.What is the next value?
Want to try another sequence?(Y/N)
The first 2 value is 5,12.What is the next value?
Want to try another sequence?(Y/N)
num_of_rights:15 num_of_tries:15

代碼實作（C++）

#include <iostream>
#include <cstdio>
using namespace std;

int main()
{
	int a1=3,a2=5,i=0,num,sum_t=0,sum_Y=0;
	int h[6][10]={{1,1,2,3,5,8,13,21},{1,3,4,7,11,18,29,47},{1,2,5,12,29,70,169,408},{1,3,6,10,15,21,28,36},{1,4,9,16,25,36,49,64},{1,5,12,22,35,51,70,92}};
	int count=0; 
	int a[6]={0};
	
	char ch,ch2;
	bool go1=true,go2=true;
	while(1)
	{	
		if(i<1)
		{	
			cout << "The first 2 value is " << h[count][a[count]] << ',' << h[count][a[count]+1] << ".What is the next value?" << endl;	
		} 
        i++;    
		if(i<=100&&i>=1)	
			cin >> num;
		while(1)
		{
			if(num!=h[count][a[count]+2]&&i==1)
			{	
                printf("Nice guess but not quite it.\n");
				sum_t++;
			}
			if(num!=h[count][a[count]+2]&&i==2)	
			{
                printf("Wrong a second time.\n");
				sum_t++;
			}
			if(num!=h[count][a[count]+2]&&i==3)
			{
                printf("This is harder than it looks.\n");
				sum_t++;
			}
			if(num!=h[count][a[count]+2]&&i==4)
			{
				sum_t++;
                printf("It must be getting pretty frustrating by now!\n");
                
			}
			if(num!=h[count][a[count]+2])
			{
				printf("Do you want to guess again?\n");	
				cin >> ch2;
				if(ch2=='Y')
				{
					break;
				}
			} 
			if(num == h[count][a[count]+2]||ch2=='N')
			{	
				i=0;
				if(num==h[count][a[count]+2])
				{
					sum_Y++;
					sum_t++;
				}
                printf("Want to try another sequence?(Y/N)\n");
                switch(count)
                {
                	case 0:
						if(a[count]<7) a[count]++;
						else a[count]=0; break;
					case 1:
						if(a[count]<7) a[count]++;
						else a[count]=0; break;
					case 2:
						if(a[count]<7) a[count]++;
						else a[count]=0; break;
					case 3:
						if(a[count]<7) a[count]++;
						else a[count]=0; break;
					case 4:
						if(a[count]<7) a[count]++;
						else a[count]=0; break;
					case 5:
						if(a[count]<7) a[count]++;
						else a[count]=0; break;	
				}
				count++;
				if(count>5)
					count=0;
				cin >> ch;
				if(ch == 'Y')
					break;
				else
				{
					printf("num_of_rights:%d num_of_tries:%d",sum_Y,sum_t);
					exit(0);
				} 
			}
		}
	}
	return 0;
}