我正在嘗試將“Project”物件的“role”引數與下面的 myProjects 陣列中的“id”和“title”引數相結合：
struct Project: Identifiable {
var id: String
var title: String
var role: String
}
var myProjects = [Project(id: "1", title: "Sunset", role: "2nd AD"),
Project(id: "2", title: "Lights", role: "Mix Tech"),
Project(id: "2", title: "Lights", role: "Sound Mixer"),
Project(id: "3", title: "Beach", role: "Producer")]
var updatedProjects: [Project] = []
// The goal is to update myProjects to show the following:
updatedProjects = [Project(id: "1", title: "Sunset", role: "2nd AD"),
Project(id: "2", title: "Lights", role: "Mix Tech & Sound Mixer"),
Project(id: "3", title: "Beach", role: "Producer"]
這是我到目前為止所嘗試的，結果是給我 myProjects 陣列中每個專案的角色引數的重復組合。
var dupProjects = myProjects
for myProject in myProjects {
for dupProject in dupProjects {
if myProject.id == dupProject.id {
let combinedRoles = "\(myProject.role) & \(dupProject.role)"
updatedProjects.append(Project(id: myProject.id,
title: myProject.title,
role: combinedRoles))
}
}
}
print(updatedProjects)
// [__lldb_expr_48.Project(id: "1", title: "Sunset", role: "2nd AD & 2nd AD"),
__lldb_expr_48.Project(id: "2", title: "Lights", role: "Mix Tech & Mix Tech"),
__lldb_expr_48.Project(id: "2", title: "Lights", role: "Mix Tech & Sound Mixer"),
__lldb_expr_48.Project(id: "2", title: "Lights", role: "Sound Mixer & Mix Tech"),
__lldb_expr_48.Project(id: "2", title: "Lights", role: "Sound Mixer & Sound Mixer"),
__lldb_expr_48.Project(id: "3", title: "Beach", role: "Producer & Producer")]
uj5u.com熱心網友回復：
您可以使用字典將它們分組id，組合角色，然后將組轉換回單個Project
let combined = Dictionary(grouping: myProjects) { element in
return element.id
}.compactMapValues { projects -> Project? in
var first = projects.first
first?.role = projects.map { $0.role }.joined(separator: " & ")
return first
}.values.map { $0 }
轉載請註明出處，本文鏈接：https://www.uj5u.com/gongcheng/313513.html