【C語言】三子棋小游戲詳解-有解無憂

在用c語言實作三子棋小游戲之前，我們應當了解三子棋的游戲規則：在九宮格棋盤上，哪一方三個棋子連成一線（一行或一列或對角線）即判定哪一方勝利，

以下為源代碼：

1.首先列印出選單，

void   menu()
{
 printf("**********************************\n");
 printf("**********************************\n");
 printf("*****     0.play     *************\n");
 printf("*****     1.exit     *************\n");
 printf("**********************************\n");
}         
menu();
 do
 {
  printf("請輸入要選的的選項: ");
  scanf("%d",&input);
  switch (input)
  {
  case 0:
    game();
    break; 
  case 1:
    printf("退出游戲");
    break;
  default:
   printf("請輸入要選的選項:\n");
   break;
  }
 } while (input);

2.創建一個二維陣列board用來儲存三子棋的元素，并對其進行初始化，

void Initboard(char board[ROW][COL], int row, int col)
{
 int i = 0;
 int j = 0;
 for (i = 0; i < row; i++)
 {
  for (j = 0; j < col; j++)
  {
   board[i][j] = ' ';
  }
 }
}

3.列印九宮格棋盤，

void Displayboard(char board[ROW][COL], int row, int col)    //列印棋盤
{
 int i;
 int j;
 for (i = 0; i < row; i++)
 {
  for (j = 0; j < col ; j++)
  {
   printf(" %c ", board[i][j]);
   if (j == col - 1)
    continue;
   printf("|");
  }
  printf("\n");
  if (i < row - 1)
   printf("-----------\n");
 }
}

4.使用Playermove和Computermove函式來對board陣列進行更改，模擬玩家和電腦落子情況，

void Playermove(char board[ROW][COL])    //玩家輸入坐標
{
 while (1)
 {
  int x = 0;
  int y = 0;
  printf("請玩家輸入坐標");
  scanf_s("%d %d", &x, &y);
  if (x <= ROW && x >= 1 && y <= COL && y >= 1)    //判斷輸入的坐標是否越界

  {
   if (board[x - 1][y - 1] == ' ')                //輸入的坐標必須為空才可以落子
   {
    board[x - 1][y - 1] = '*';
    break;
   }
   else
    printf("坐標被占用，請重新輸入\n");
  }
  else
   printf("坐標有誤，請重新輸入\n");
  }
 }
 void Computermove(char board[ROW][COL])    //電腦輸入坐標
{
 int x = 0;
 int y = 0;
 while (1)
 {
  x = rand() % 3; 		    //使用rand函式生成亂數并取余得到電腦落子坐標
  y = rand() % 3;
  if (board[x][y] == ' ')
  {
   printf("電腦輸入坐標%d %d\n", x+1, y+1);
   board[x][y] = '#';
   break;                    //列印后跳出回圈
  }
 }
}

5.玩家和電腦每落一次子，就要進行一次判斷是否獲勝，根據回傳值來進行判斷游戲結果，

int Iswin(char board[ROW][COL], int row, int col)      //判斷誰獲勝
{
 int i;
 int j;
 //1為玩家獲勝          0為電腦獲勝       2為平局
 for (i = 0; i < row; i++)
 {
  if (board[i][0] == board[i][1] && board[i][1] == board[i][2] && board[i][1] == '*')        //判斷同一行是否相等
   return  1;     
  else if (board[i][0] == board[i][1] && board[i][1] == board[i][2] && board[i][1] == '#')
   return 0;
 }
 for (j = 0; j < col; j++)
 {
  if (board[0][j] == board[1][j] && board[1][j] == board[2][j] && board[1][j] == '*')      //判斷同一列是否相等
   return 1;
  else if (board[0][j] == board[1][j] && board[1][j] == board[2][j] && board[1][j] == '#')
   return 0;
 }
 if (board[0][0] == board[1][1] && board[1][1] == board[2][2] && board[1][1] == '*')   //判斷左對角線是否相等
  return 1;
 else if (board[0][0] == board[1][1] && board[1][1] == board[2][2] && board[1][1] == '#')
  return 0;
 if (board[0][2] == board[1][1] && board[1][1] == board[2][0] && board[1][1] == '*')   //判斷右對角線是否相等
  return 1;
 else if (board[0][2] == board[1][1] && board[1][1] == board[2][0] && board[1][1] == '#')
  return 0;
 if (Full(board, ROW, COL))   //判斷是否平局
  return 2;
 return 3;                           //回傳3為繼續進行游戲
}

6.函式宣告，宏定義，函式的定義實作，測驗，

#include<stdio.h>
#include<string.h>
#include<time.h>
#include<stdlib.h>
#include"game.h"
# define _CRT_SECURE_NO_WARNINGS
#define ROW 3
#define COL 3

void Initboard(char board[ROW][COL], int row, int col);
void Displayboard(char board[ROW][COL], int row, int col);
void Playermove(char board[ROW][COL]);
void Computer(char board[ROW][COL]);
int Iswin(char board[ROW][COL], int row, int col);
int Full(char board[ROW][COL], int row, int col);
void   menu()
{
 printf("**********************************\n");
 printf("**********************************\n");
 printf("*****     0.play     *************\n");
 printf("*****     1.exit     *************\n");
 printf("**********************************\n");
}
void game()
{
 char board[ROW][COL] = { 0 };
 int ret;
 Initboard(board, ROW, COL);   //用Initboard函式初始化陣列，并用‘ ’初始化陣列
 printf("游戲開始\n");
 while (1)
 {
  Playermove(board);   //玩家輸入坐標
  Displayboard(board, ROW, COL);
  ret = Iswin(board, ROW, COL);   //判斷是否獲勝
  if (ret == 1)
  {
   printf("玩家獲勝");
   break;
  }
  else if (ret == 0)
  {
   printf("電腦獲勝");
   break;
  }
  else if (ret == 2)
  {
   printf("平局");
   break;
  }
  printf("\n\n");
  Computer(board);  //電腦輸入坐標
  Displayboard(board, ROW, COL);
  ret = Iswin(board, ROW, COL);   //判斷是否獲勝
  if (ret == 1)
  {
   printf("玩家獲勝");
   break;
  }
  else if (ret == 0)
  {
   printf("電腦獲勝");
   break;
  }
  else if (ret == 2)
  {
   printf("平局");
   break;
  }
  printf("\n\n");
 }
}
int main()
{
 int input = 0;
 srand((unsigned int)time(NULL));
 menu();
 do
 {
  printf("請輸入要選的的選項: ");
  scanf("%d",&input);
  switch (input)
  {
  case 0:
    game();
    break; 
  case 1:
    printf("退出游戲");
    break;
  default:
   printf("請輸入要選的選項:\n");
   break;
  }
 } while (input);
}
void Initboard(char board[ROW][COL], int row, int col)
{
 int i = 0;
 int j = 0;
 for (i = 0; i < row; i++)
 {
  for (j = 0; j < col; j++)
  {
   board[i][j] = ' ';
  }
 }
}

void Displayboard(char board[ROW][COL], int row, int col)    //列印棋盤
{
 int i;
 int j;
 for (i = 0; i < row; i++)
 {
  for (j = 0; j < col ; j++)
  {
   printf(" %c ", board[i][j]);
   if (j == col - 1)
    continue;
   printf("|");
  }
  printf("\n");
  if (i < row - 1)
   printf("-----------\n");
 }
}

void Playermove(char board[ROW][COL])    //玩家輸入坐標
{
 while (1)
 {
  int x = 0;
  int y = 0;
  printf("請玩家輸入坐標");
  scanf_s("%d %d", &x, &y);
  if (x <= ROW && x >= 1 && y <= COL && y >= 1)
  {
   if (board[x - 1][y - 1] == ' ')
   {
    board[x - 1][y - 1] = '*';
    break;
   }
   else
    printf("坐標被占用，請重新輸入\n");
  }
  else
   printf("坐標有誤，請重新輸入\n");
 }
}

void Computer(char board[ROW][COL])    //電腦輸入坐標
{
 int x = 0;
 int y = 0;
 while (1)
 {
  x = rand() % 3;
  y = rand() % 3;
  if (board[x][y] == ' ')
  {
   printf("電腦輸入坐標%d %d\n", x+1, y+1);
   board[x][y] = '#';
   break;                    //列印后跳出回圈
  }
 }
}

int Iswin(char board[ROW][COL], int row, int col)      //判斷誰獲勝
{
 int i;
 int j;
 //1為玩家獲勝          0為電腦獲勝       2為平局
 for (i = 0; i < row; i++)
 {
  if (board[i][0] == board[i][1] && board[i][1] == board[i][2] && board[i][1] == '*')        //判斷同一行是否相等
   return  1;     
  else if (board[i][0] == board[i][1] && board[i][1] == board[i][2] && board[i][1] == '#')
   return 0;
 }
 for (j = 0; j < col; j++)
 {
  if (board[0][j] == board[1][j] && board[1][j] == board[2][j] && board[1][j] == '*')      //判斷同一列是否相等
   return 1;
  else if (board[0][j] == board[1][j] && board[1][j] == board[2][j] && board[1][j] == '#')
   return 0;
 }
 if (board[0][0] == board[1][1] && board[1][1] == board[2][2] && board[1][1] == '*')   //判斷左對角線是否相等
  return 1;
 else if (board[0][0] == board[1][1] && board[1][1] == board[2][2] && board[1][1] == '#')
  return 0;
 if (board[0][2] == board[1][1] && board[1][1] == board[2][0] && board[1][1] == '*')   //判斷右對角線是否相等
  return 1;
 else if (board[0][2] == board[1][1] && board[1][1] == board[2][0] && board[1][1] == '#')
  return 0;
 if (Full(board, ROW, COL))   //判斷是否平局
  return 2;
 return 3;                           //回傳3為繼續進行游戲
}

int Full(char board[ROW][COL], int row, int col)   //判斷棋盤是否下滿
{
 int i;
 int j;
 for (i = 0; i < row; i++)
 {
  for (j = 0; j < col; j++)
  {
   if (board[i][j] == ' ')
    return 0;     //此時棋盤未滿
  }
 }
 return 1;        //此時棋盤已滿
}

轉載請註明出處，本文鏈接：https://www.uj5u.com/yidong/186377.html

標籤：其他

上一篇：華為工程師總結的LeetCode刷題筆記提供下載，太優秀了

下一篇：人工智能2020秋季總結