我想做一些事情，如果我鍵入“1”，則數字將升序（x ），如果我鍵入“2”，則數字將降序。x 作業正常，但如果我使用 x--，它將無限回圈
public static void main(String[] args) {
Scanner scan = new Scanner (System.in);
System.out.print("Enter starting loop:");
int start = scan.nextInt();
System.out.print("Enter ending loop:");
int end = scan.nextInt();
System.out.print("Choose Order:");
int n = scan.nextInt();
if (n==1) {
for (int x=start;x<=end;x--){
System.out.print(x "\t");
}
}
}
uj5u.com熱心網友回復：
對于第二個回圈，將其更改為 x>=end 而不是當前的 x<=end 。基本上你必須做兩個 for 回圈：
public static void main(String[] args) {
Scanner scan = new Scanner (System.in);
System.out.print("Enter starting loop:");
int start = scan.nextInt();
System.out.print("Enter ending loop:");
int end = scan.nextInt();
System.out.print("Choose Order: ");
int n = scan.nextInt();
if(n==1)
{
for (int x=end;x>=start;x--){ //If they want to go from end to 0
System.out.print(x "\t");
}
else
{
for (int x=start;x<=end;x ){ //So when they want it to go from 0 to end
System.out.print(x "\t");
}
uj5u.com熱心網友回復：
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
System.out.print("Enter starting loop:");
int start = scan.nextInt();
System.out.print("Enter ending loop:");
int end = scan.nextInt();
System.out.print("Choose Order:");
int n = scan.nextInt();
boolean isAscending = n == 1;
for (int i = start; (isAscending) ? i <= end : i >= end; i = (isAscending) ? i 1 : i - 1) {
System.out.print(i "\t");
}
}
示例：從 1 到 10，順序為 1
Enter starting loop:1
Enter ending loop:10
Choose Order:1
1 2 3 4 5 6 7 8 9 10
示例：從 10 到 1，順序為 2
Enter starting loop:10
Enter ending loop:1
Choose Order:2
10 9 8 7 6 5 4 3 2 1
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