我想得到回圈產生的亂數的總和 這是我的回圈
for i in range(1, rolls 1):
random1 = str([random.randint(1, 6)])
print(f'Roll {i}:' random1)
The output looks like this
Roll 1:[2]
Roll 2:[5]
Roll 3:[1]
Roll 4:[1]
Roll 5:[2]
Roll 6:[4]
Roll 7:[2]
Roll 8:[5]
Roll 9:[1]
Roll 10:[6]
我如何從 [括號] 中獲得總和？
uj5u.com熱心網友回復：
使用變數來跟蹤總和：
total = 0
for i in range(1, rolls 1):
n = random.randint(1, 6)
total = n
print(f'Roll {i}: [{n}]')
print(f"Total: {total}")
使用sum：
nums = [random.randint(1, 6) for i in range(1, rolls 1)]
for i, n in enumerate(nums):
print(f'Roll {i}: [{n}]')
print(f"Total: {sum(nums)}")
uj5u.com熱心網友回復：
或者，這里有一個:=在 3.8 中使用運算子的更短的方法：
total = 0
for i in range(1, rolls 1):
total = (n := random.randint(1, 6))
print(f'Roll {i}: [{n}]')
print(f"Total: {total}")
uj5u.com熱心網友回復：
sum = 0
for i in range(1, rolls 1):
rand = random.randint(1, 6)
sum = rand
random1 = str(rand)
print(f'Roll {i}:' random1)
print(sum)
uj5u.com熱心網友回復：
您可以定義一個將所有亂數相加的變數
sum_number = 0
for i in range(1, rolls 1):
random_number = random.randint(1, 6)
random1 = str([random_number])
print(f'Roll {i}:' random1)
sum_number = random_number
print(sum_number)
或者你可以重寫它
random_number_list = [random.randint(1, 6) for _ in range(rolls)]
sum_number = sum(random_number_list)
# print random number
for i,random_number in enumerate(random_number_list):
print(f'Roll {i 1}:' random1)
print(sum_number)
如果不需要看列印，只需要前兩行代碼
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