我想查詢一個JSONmysql欄位如下:
json:
{
"key1": [
{
"firstname": "jane"
},
{
"firstname": "john"
}
]
}
我想搜索“key1”,并提取該[0].firstname欄位,在本例中為jane.
但是我怎樣才能用JSON_EXTRACT()或類似的方法實作這一點?
uj5u.com熱心網友回復:
mysql> set @j = '...your json example...';
mysql> select json_unquote(json_extract(@j, '$.key1[0].firstname')) as fn;
------
| fn |
------
| jane |
------
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標籤:mysql mysql-json
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