我有字串
ss='/users/parun/kk/jdk/bin/\x1b[01;31m\x1b[kjava\x1b[m\x1b[k'
How to get output
'/users/parun/kk/jdk/bin' only from the above
我試過
import re
re.split(r'\/\\')
但不作業
uj5u.com熱心網友回復:
正則運算式搜索可能是這里的最佳選擇:
ss = '/users/parun/kk/jdk/bin/\x1b[01;31m\x1b[kjava\x1b[m\x1b[k'
path = re.findall(r'^.*/jdk/bin', ss)[0]
print(path) # /users/parun/kk/jdk/bin
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