我只需要檢測出現在那里的黑色矩形，但由于某種原因，我的代碼沒有檢測到它，但它確實檢測到了許多其他東西。
import cv2
img=cv2.imread('vision.png') #read image
gray = cv2.cvtColor(img, cv2.COLOR_BGR2GRAY)
Blur=cv2.GaussianBlur(gray,(5,5),1) #apply blur to roi
Canny=cv2.Canny(Blur,10,50) #apply canny to roi
#Find my contours
contours =cv2.findContours(Canny,cv2.RETR_EXTERNAL,cv2.CHAIN_APPROX_NONE)[0]
cntrRect = []
for i in contours:
epsilon = 0.05*cv2.arcLength(i,True)
approx = cv2.approxPolyDP(i,epsilon,True)
if len(approx) == 4:
cv2.drawContours(img,cntrRect,-1,(0,255,0),2)
cv2.imshow('Image Rect ONLY',img)
cntrRect.append(approx)
cv2.waitKey(0)
cv2.destroyAllWindows()
如何僅檢測影像中出現的黑色矩形
但是這段代碼檢測了更多的矩形，我不想要whis，但我只想檢測黑色的countour矩形
uj5u.com熱心網友回復：
這是在 Python/OpenCV 中執行此操作的一種方法。
閾值影像。然后使用形態學來填充矩形。然后得到最大的輪廓并在輸入上繪制。
輸入：
import cv2
import numpy as np
# load image
img = cv2.imread("black_rectangle_outline.png")
# convert to grayscale
gray = cv2.cvtColor(img, cv2.COLOR_BGR2GRAY)
# threshold
thresh = cv2.threshold(gray, 30, 255, cv2.THRESH_BINARY)[1]
# apply close morphology
kernel = np.ones((111,111), np.uint8)
morph = cv2.morphologyEx(thresh, cv2.MORPH_OPEN, kernel)
# invert so rectangle is white
morph = 255 - morph
# get largest contour and draw on copy of input
result = img.copy()
contours = cv2.findContours(morph, cv2.RETR_EXTERNAL, cv2.CHAIN_APPROX_SIMPLE)
contours = contours[0] if len(contours) == 2 else contours[1]
big_contour = max(contours, key=cv2.contourArea)
cv2.drawContours(result, [big_contour], 0, (255,255,255), 1)
# write result to disk
cv2.imwrite("black_rectangle_outline_thresh.png", thresh)
cv2.imwrite("black_rectangle_outline_morph.png", morph)
cv2.imwrite("black_rectangle_outline_result.png", result)
# display results
cv2.imshow("THRESH", thresh)
cv2.imshow("MORPH", morph)
cv2.imshow("RESULT", result)
cv2.waitKey(0)
cv2.destroyAllWindows()
閾值影像：
形態學影像：
結果：
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