我想創建一個沒有性別欄位的新物件陣列。錯誤在哪里？
let collections = [
{ name: "Tom", gender: "male", age: 12 },
{ name: "Becky", gender: "female", age: 11 },
{ name: "Huck", gender: "male", age: 13 }
];
let newCollections = collections.slice();
let operations = {
select: function () {
let args = [].slice.call(arguments);
for (let i = 0; i < newCollections.length; i ) {
for (let key in newCollections[i]) {
for (let j = 0; j < args.length; j ) {
if (key !== args[j]) {
delete key;
return newCollections;
} } } } } };
const result = operations.select("name", "age");// the list of fields to save
console.log(result);uj5u.com熱心網友回復：
您可以創建一個omit()函式，該函式將回傳一個沒有給定屬性的物件。
然后我們可以通過以下Array.map()方式運行陣列中的每個專案：
let collections = [ { name: "Tom", gender: "male", age: 12 }, { name: "Becky", gender: "female", age: 11 }, { name: "Huck", gender: "male", age: 13 } ];
function omit(obj, field) {
return (({ [field]: _, ...result }) => result)(obj);
}
let newCollections = collections.map(person => omit(person, 'gender'));
console.log('New collections:', newCollections);.as-console-wrapper { max-height: 100% !important; top: 0; }uj5u.com熱心網友回復：
您可以使用 map 方法來做到這一點：
const array_without_gender = collections.map(el => {
return {name: el.name, age: el.age};
})
此代碼將創建由沒有性別鍵的物件填充的新陣列，
轉載請註明出處，本文鏈接：https://www.uj5u.com/yidong/374250.html
標籤：javascript for循环 javascript对象
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