我有這個資料框
----- ------- ----------- ------------------- -----
|empID|Zipcode|ZipCodeType|City |State|
----- ------- ----------- ------------------- -----
|1000 |704 |STANDARD |PARC PARQUE |PR |
|1000 |704 |STANDARD |PASEO COSTA DEL SUR|PR |
|1001 |709 |STANDARD |BDA SAN LUIS |PR |
|1001 |76166 |UNIQUE |CINGULAR WIRELESS |TX |
|1002 |76177 |STANDARD |FORT WORTH |TX |
|1002 |76177 |STANDARD |FT WORTH |TX |
|1003 |704 |STANDARD |URB EUGENE RICE |PR |
|1003 |85209 |STANDARD |MESA |AZ |
|1004 |85210 |STANDARD |MESA |AZ |
|1004 |32046 |STANDARD |HILLIARD |FL |
----- ------- ----------- ------------------- -----
對于每個 empID 需要列印其值不同的列名。
----- ---------------------------------
|empID|nonMatchingColumnNames |
----- ---------------------------------
|1002 |City |
|1000 |City |
|1001 |State, City, ZipCodeType, Zipcode|
|1003 |State, City, Zipcode |
|1004 |State, City, Zipcode |
----- ---------------------------------
我采取的策略是,構建一個結構并收集所有值。檢查每個集合的計數是否> 1,然后列印列名稱。這是我的代碼
val schema = new StructType()
.add("empID", IntegerType, true)
.add("Zipcode", StringType, true)
.add("ZipCodeType", StringType, true)
.add("City", StringType, true)
.add("State", StringType, true)
val idColumn = "empID"
val dfJSON = dfFromText.withColumn("jsonData",from_json(col("value"),schema))
.select("jsonData.*")
dfJSON.printSchema()
dfJSON.show(false)
val aggMap = dfJSON.columns
.filterNot(x => x == idColumn)
.map(colName => (collect_set(colName).alias(s"${colName}_asList"), s"${colName}_asList"))
aggMap.foreach(println)
val aggMapColumns = aggMap.map(x => x._1)
val columnsAsList = dfJSON.groupBy(col(idColumn)).agg(aggMapColumns.head, aggMapColumns.tail : _ *)
columnsAsList.show(false)
val combinedDF = columnsAsList.select(col(idColumn), struct(
aggMap.map(x => col(x._2)) : _ * ).alias("combined_struct")
)
combinedDF.printSchema()
combinedDF.show(false)
val columnsToCompare = dfJSON.columns.filterNot(x => x == idColumn).zipWithIndex.map({ case (x,y) => (y,x)})
val output = combinedDF.rdd.map({row => {
val empNo = row.getAs[Int](0)
val conbinedStruct: Row = row.getAs[AnyRef]("combined_struct").asInstanceOf[Row]
val nonMatchingColumns = columnsToCompare.foldLeft(List[String]())((acc, item) => {
val counts = conbinedStruct.getAs[Seq[String]](item._1).length
if (counts == 1) acc else item._2 :: acc
})
(empNo, nonMatchingColumns.mkString(", "))
}}).toDF(idColumn, "nonMatchingColumnNames")
output.show(false)
它在我的本地機器上作業得非常好,當我將它移植到 spark-shell(它是一個臨時查詢)時,當我嘗試將資料幀轉換為 RDD 并遍歷結構中的每個專案時,我遇到了空指標例外。
uj5u.com熱心網友回復:
您只能使用 spark 的內置函式來獲取包含值不唯一的列串列的字串:
- 用于
countDistinct確定特定列中是否有特定列中的多個值empID - 如果 count distinct 大于 2,則保存列的名稱,使用
when - 迭代列并將此迭代保存到陣列中
array - 使用此陣列構建一個字串
concat_ws
完整代碼如下:
import org.apache.spark.sql.functions.{array, concat_ws, countDistinct, lit, when}
val output = dfJSON.groupBy("empID").agg(
concat_ws(
", ",
array(dfJSON.columns.filter(_ != "empID").map(c => when(countDistinct(c) > 1, lit(c))): _*)
).as("nonMatchingColumnNames")
)
使用您的輸入資料框,您將獲得以下輸出:
----- ---------------------------------
|empID|nonMatchingColumnNames |
----- ---------------------------------
|1002 |City |
|1000 |City |
|1001 |Zipcode, ZipCodeType, City, State|
|1003 |Zipcode, City, State |
|1004 |Zipcode, City, State |
----- ---------------------------------
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