更新字典中的值串列（累積更新）

背景關系：我有一個包含一些足球比賽結果的字典，我想創建第二個字典，將這些值顯示為包含足球比賽結果的串列。

例如，我有這個初始字典：

dict_results = {('FCP', 'SLB'): (1, 4),
 ('FCP', 'SCP'): (2, 5),
 ('SLB', 'FCP'): (2, 6),
 ('SLB', 'SCP'): (1, 5),
 ('SCP', 'FCP'): (2, 4),
 ('SCP', 'SLB'): (1, 4)}

我想得到這種格式：

tabela = {'FCP': [win, draw, loss, scored_goals, suff_goals, points],
 'SLB': [win, draw, loss, scored_goals, suff_goals, points],
 'SCP': [win, draw, loss, scored_goals, suff_goals, points]}

我試圖做這樣的事情：

tabela = {}

for teams,goals in dict_results.items():
    win = 0
    draw = 0
    loss = 0
    scored_goals = 0
    suff_goals = 0
    points = 0

    print(teams,goals)
    if teams[0] not in tabela:
        tabela[teams[0]] = [win, draw, loss, scored_goals, suff_goals, points]
    

    if goals[0] > goals[1]:
        #teams[0] update
        win = 1
        scored_goals = goals[0]
        suff_goals = goals[1]
        points = 3
        tabela[teams[0]].update([win,draw,loss,scored_goals,suff_goals,points])
    elif goals[0] == goals[1]:
        draw = 1
        scored_goals = goals[0]
        suff_goals = goals[1]
        points = 1
        tabela[teams[0]].update([win,draw,loss,scored_goals,suff_goals,points])
        tabela[teams[1]].update([win,draw,loss,scored_goals,suff_goals,points])
    elif goals[0] < goals[1]:
        ...

但是值保持在 0（它們實際上并沒有更新）這真的很有意義，因為每次迭代我基本上都是在“重置”值，即使值按照我想要的方式更新，我也不會并沒有真正獲得累積值。

我怎么做才能比較每個團隊的目標并相應地更新結果？例如，在元組 ('FCP','SLB') 中，'FCP' 的進球數為 1，SLB 的進球數為 4，這意味著 'FCP' 進了 4 個球，進了 1 個球，沒有得分，將損失增加 1 和 'SLB' 將勝利增加 1，遭受 1 個進球，打進 4 個進球并獲得 3 分（不使用字典或串列理解）

先感謝您！

uj5u.com熱心網友回復：

另外，您正在回圈遍歷兩個團隊，但您只記錄第一個團隊的結果。你可以用一個額外的 for 回圈來獲得兩個團隊。

tabela = {}

for teams,goals in dict_results.items():
    for iter in range(len(teams)):
        team = teams[iter]
        win = 0
        draw = 0
        loss = 0
        scored_goals = 0
        suff_goals = 0
        points = 0
        
        if iter == 0:
            n = 0
            m = 1
        else:
            n = 1
            m = 0

        if team not in tabela:
            tabela[team] = [win, draw, loss, scored_goals, suff_goals, points]
        
        if goals[n] > goals[m]:
            win, draw, loss, scored_goals, suff_goals, points = tabela[team]
            win  = 1
            scored_goals  = goals[n]
            suff_goals  = goals[m]
            points  = 3
            tabela[team] = [win,draw,loss,scored_goals,suff_goals,points]
        elif goals[n] < goals[m]:
            win, draw, loss, scored_goals, suff_goals, points = tabela[team]
            win  = 0
            scored_goals  = goals[n]
            suff_goals  = goals[m]
            points  = 0
            tabela[team] = [win,draw,loss,scored_goals,suff_goals,points]
        elif goals[n] == goals[m]:
            win, draw, loss, scored_goals, suff_goals, points = tabela[team]
            win  = 0
            scored_goals  = goals[n]
            suff_goals  = goals[m]
            points  = 1
            tabela[team] = [win,draw,loss,scored_goals,suff_goals,points]
        

print(tabela)

 >>{'FCP': [2, 0, 0, 13, 13, 6], 'SLB': [2, 0, 0, 11, 13, 6], 'SCP': [2, 0, 0, 13, 11, 6]}

根據您的迭代iter，n并m切換數字。通過這種方式，if 陳述句會檢查第 1 次迭代中團隊 1 的分數和第 2 次迭代中團隊 2 的分數。

uj5u.com熱心網友回復：

你是對的，看起來你確實在每次迭代中“重置”這些值。在 Python 中，該.update函式不添加值，它只是替換字典條目。您仍然可以使用tabela[team].update，您只需要自己添加之前的值。

這是如何做到這一點的代碼示例：

    ...
    if goals[0] > goals[1]:
        #teams[0] update
        win, draw, loss, scored_goals, suff_goals, points = tabela[teams[0]]
        win  = 1
        scored_goals  = goals[0]
        suff_goals  = goals[1]
        points  = 3
        tabela[teams[0]].update([win,draw,loss,scored_goals,suff_goals,points])
    elif goals[0] == goals[1]:
        ...
    elif goals[0] < goals[1]:
        ...

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