0xC0000005：訪問沖突讀取位置0x005EF9E4

我遇到了句柄問題。我在 DWORD WINAPI 函式中播放 Bytebeat（以位元組為單位的音樂）。當我嘗試終止并關閉執行緒時，它直接給了我標題中的錯誤。這是我的代碼：

#include <windows.h>
#pragma comment(lib, "Winmm.lib")

DWORD WINAPI bytebeat1(LPVOID) {
    while (1) {
        HWAVEOUT hwo = 0;
        WAVEFORMATEX wfx = { WAVE_FORMAT_PCM, 1, 11000, 11000, 1, 8, 0 };
        waveOutOpen(&hwo, WAVE_MAPPER, &wfx, 0, 0, CALLBACK_NULL);

        char buffer[11000 * 6];

        for (DWORD t = 0; t < sizeof(buffer); t  )
            buffer[t] = static_cast<char>(t & t   t / 256) - t * (t >> 15) & 64;

        WAVEHDR hdr = { buffer, sizeof(buffer), 0, 0, 0, 0, 0, 0 };
        waveOutPrepareHeader(hwo, &hdr, sizeof(WAVEHDR));
        waveOutWrite(hwo, &hdr, sizeof(WAVEHDR));
        waveOutUnprepareHeader(hwo, &hdr, sizeof(WAVEHDR));
        waveOutClose(hwo);
        Sleep(6000);
    }
}

DWORD WINAPI bytebeat2(LPVOID) {
    while (1) {
        HWAVEOUT hwo = 0;
        WAVEFORMATEX wfx = { WAVE_FORMAT_PCM, 1, 8000, 8000, 1, 8, 0 };
        waveOutOpen(&hwo, WAVE_MAPPER, &wfx, 0, 0, CALLBACK_NULL);

        char buffer[8000 * 6];

        for (DWORD t = 0; t < sizeof(buffer); t  )
            buffer[t] = static_cast<char>(t, t / 5) >> t / 25 & t / 55 ^ t & 255 ^ (t / 150) ^ 2508025 * 24240835810 & (t / 100) * t / 6000 ^ 5000 * t / 2500 ^ 25 * t / 24;

        WAVEHDR hdr = { buffer, sizeof(buffer), 0, 0, 0, 0, 0, 0 };
        waveOutPrepareHeader(hwo, &hdr, sizeof(WAVEHDR));
        waveOutWrite(hwo, &hdr, sizeof(WAVEHDR));
        waveOutUnprepareHeader(hwo, &hdr, sizeof(WAVEHDR));
        waveOutClose(hwo);
        Sleep(6000);
    }
}

int main() {
    HANDLE beat1 = CreateThread(0, 0, bytebeat1, 0, 0, 0);
    Sleep(6000);
    TerminateThread(beat1, 0); CloseHandle(beat1);
    Sleep(1000);
    HANDLE beat2 = CreateThread(0, 0, bytebeat2, 0, 0, 0);
    Sleep(6000);
    TerminateThread(beat2, 0); CloseHandle(beat2);
}

我不知道為什么會這樣。唯一的修復是用 G 編譯它，但我想要它，所以我可以構建它。任何幫助表示贊賞。謝謝！

uj5u.com熱心網友回復：

當您呼叫 TerminateThread 時，您基本上是在強制使執行緒崩潰。它們仍然有自己的堆疊分配和 Windows 資源句柄。它們沒有正確清理，導致您的崩潰。

這是一個簡單的示例，說明如何在沒有任何錯誤的情況下關閉執行緒。在實際場景中，這是一個不專業的解決方案，但它顯示了您需要做的最低限度的作業。

#include <windows.h>
#pragma comment(lib, "Winmm.lib")

volatile bool quit1 = false;
volatile bool quit2 = false;

DWORD WINAPI bytebeat1(LPVOID) {
    while (!quit1) {
        HWAVEOUT hwo = 0;
        WAVEFORMATEX wfx = { WAVE_FORMAT_PCM, 1, 11000, 11000, 1, 8, 0 };
        waveOutOpen(&hwo, WAVE_MAPPER, &wfx, 0, 0, CALLBACK_NULL);

        char buffer[11000 * 6];

        for (DWORD t = 0; t < sizeof(buffer); t  )
            buffer[t] = static_cast<char>(t & t   t / 256) - t * (t >> 15) & 64;

        WAVEHDR hdr = { buffer, sizeof(buffer), 0, 0, 0, 0, 0, 0 };
        waveOutPrepareHeader(hwo, &hdr, sizeof(WAVEHDR));
        waveOutWrite(hwo, &hdr, sizeof(WAVEHDR));
        waveOutUnprepareHeader(hwo, &hdr, sizeof(WAVEHDR));
        waveOutClose(hwo);
        Sleep(6000);
    }

    return 0;
}

DWORD WINAPI bytebeat2(LPVOID) {
    while (!quit2) {
        HWAVEOUT hwo = 0;
        WAVEFORMATEX wfx = { WAVE_FORMAT_PCM, 1, 8000, 8000, 1, 8, 0 };
        waveOutOpen(&hwo, WAVE_MAPPER, &wfx, 0, 0, CALLBACK_NULL);

        char buffer[8000 * 6];

        for (DWORD t = 0; t < sizeof(buffer); t  )
            buffer[t] = static_cast<char>(t, t / 5) >> t / 25 & t / 55 ^ t & 255 ^ (t / 150) ^ 2508025 * 24240835810 & (t / 100) * t / 6000 ^ 5000 * t / 2500 ^ 25 * t / 24;

        WAVEHDR hdr = { buffer, sizeof(buffer), 0, 0, 0, 0, 0, 0 };
        waveOutPrepareHeader(hwo, &hdr, sizeof(WAVEHDR));
        waveOutWrite(hwo, &hdr, sizeof(WAVEHDR));
        waveOutUnprepareHeader(hwo, &hdr, sizeof(WAVEHDR));
        waveOutClose(hwo);
        Sleep(6000);
    }

    return 0;
}

int main() {
    HANDLE beat1 = CreateThread(0, 0, bytebeat1, 0, 0, 0);
    Sleep(6000);
    quit1 = true;
    WaitForSingleObject(beat1, INFINITE);
    CloseHandle(beat1);
    Sleep(1000);
    HANDLE beat2 = CreateThread(0, 0, bytebeat2, 0, 0, 0);
    Sleep(6000);
    quit2 = true;
    WaitForSingleObject(beat2, INFINITE);
    CloseHandle(beat2);
}

uj5u.com熱心網友回復：

正如檔案所表明的那樣，您不能使用TerminateThread這種方式。相反，將呼叫替換為Sleep可中斷的睡眠函式，該函式將在請求時干凈且安全地終止執行緒。

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