Python：函式和回圈。錯誤：ValueError：以10為底的int()的無效文字：

我正在學習 Python 函式和回圈；但是，我在嘗試計算分配給回圈中整數的兩個變數時遇到錯誤，我在下面發布了我的代碼以及 draw.io 圖，以便更好地解釋我想要完成的任務：

在包含的影像中，綠色代表一個作業回圈或功能，紅色代表一個損壞的回圈或功能，白色代表尚未編碼

在包含的代碼中，回圈適用于輸入選項 m 和 l，但回圈不適用于選項 q。q 選項也不適用于 w、e 和 r 選項的添加。

PS 我還沒有在 w、e、r 或 y 選項中撰寫任何代碼（如您所見），但是我已將整數分配給 q、w、e 和 r 變數。

q = 1
w = 2
e = 3
r = 4

def exitprogram():
    print ("exiting...")
    
    

def q_function():
    Q_loop = True
    while Q_loop:
        print("Q function selected, select addition - press k to go back or x to exit")
        print("")
        Q_addition = int(input("Add Q with "))
        
        #exit program
        if Q_addition =="x":
            exitprogram()
            break
            
        
        #additions
        elif Q_addition == "w":
            q_w = q w
            print(q_w)

        if Q_addition == "k":
            start()

        #invalid input
        else:
            print("invalid input - try again")
            continue
    
    
def w_function():
    print("W function operational")
    W_addition = int(input("Add W with - to exit select x "))
    
def e_function():
    print("E function operational")
    E_addition = int(input("Add E with - to exit select x "))

def r_function():
    print("R function operational")
    R_addition = int(input("Add R with - to exit select x "))

def t_function():
    T_loop = True
    while T_loop:
        T_selection = input("T function operational - press k to go back or x to exit ")
        if T_selection == "k":
            more()
        elif T_selection == "x":
            exitprogram()
            break
            
        
        else:
            print("invalid input - try again")
            continue

def y_function():
    print("Y function operational")

def more():
    moreloop = True
    while moreloop:
        l = input ("select t or y - to go back select k to exit select x ")
        if l =="t":
            t_function()
            break
        if l =="y":
            y_function()
            break
        if l =="x":
            exitprogram()
            break
        elif l =="k":
            start()
        else:
            print("invalid input - try again")
            continue

def start():
    loop1 = True
    while loop1:
        a = input("select q, w, e or y - for more options select m or to exit select x ")
        if a == "x":
            exitprogram()
            break
        elif a == "q":
            q_function()
            break 
        elif a == "w":
            w_function()
            break
        elif a == "e":
            e_function()
            break
        elif a == "r":
            r_function()
            break

        elif a =="m":
            more()
            break
              
            
        else:
            print("invalid input - try again")
            continue
start()     

錯誤回溯包括在下面

 Traceback (most recent call last):
  File "x:/xxx/xxx/xxxx/xxxx.xx", line 115, in <module>
    start()
  File "x:/xxx/xxx/xxxx/xxxx.xx", line 95, in start
    q_function()
  File "x:/xxx/xxx/xxxx/xxxx.xx"", line 16, in q_function
    Q_addition = int(input("Add Q with "))
ValueError: invalid literal for int() with base 10: 'w'

uj5u.com熱心網友回復：

您Q_addition = int(input("Add Q with "))正試圖將輸入（x、k、e 等）轉換為 int。這會引發錯誤。此外，您的邏輯檢查字串不是 int

#exit program
if Q_addition =="x":
    Q_loop = False #set the loop variable to false to exit the loop and return to main function
#changed to elif as Q_addition can only be one option
elif Q_addition =="x":
...
elif Q_addition == "w":
#if you'd like addition with the other variables need to add them 
elif Q_addition == "e":
  q_e = q e
  print(q_e)
elif Q_addition == "r":
  q_r = q r
  print(q_r)
...
#changed to elif, see above
elif Q_addition == "k":

洗掉int()演員所以Q_addition = input("Add Q with ")

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