我有這個 JavaScript 代碼：
highlightTerm = "h=e;?l*l{o";
highlightTerm = highlightTerm.replace(/[\\;]/g, ' ');
highlightTerm = highlightTerm.replace(/([{}<>\/=:])(?=(?:[^"]|"[^"]*")*$)/g, '\\$&');
highlightTerm = highlightTerm.replace(/"/g, '\"');
highlightTerm = highlightTerm.trim();
console.log(highlightTerm); // "h\=e ?l*l\{o"
我正在嘗試找到 Java 等價物。我嘗試了以下位，它給出了不同的結果：
String highlightTerm = "h=e;?l*l{o";
highlightTerm = highlightTerm.replaceAll("[\\;]", " ");
highlightTerm = highlightTerm.replaceAll("([{}<>\\/=:])(?=(?:[^\"]|\"[^\"]*\")*$)", "\\$&");
highlightTerm = highlightTerm.replaceAll("[\"]", "\\\"");
highlightTerm = highlightTerm.trim();
System.out.println(highlightTerm); // "h=e ?l*l{o"
任何幫助深表感謝！
uj5u.com熱心網友回復：
您遇到的問題'\\$&'是 Javascript 表示整個匹配的字串，但在 Java 中并不相同。我認為Java中沒有解決這個問題的單行解決方案，但是這段代碼應該可以作業：
String highlightTerm = "h=e;?l*l{o";
highlightTerm = highlightTerm.replaceAll("[\\;]", " ");
//highlightTerm = highlightTerm.replace(/([{}<>\/=:])(?=(?:[^"]|"[^"]*")*$)/g, '\\$&');
//These lines are replacement for the above line
Pattern pattern = Pattern.compile("([{}<>\\/=:])(?=(?:[^\"]|\"[^\"]*\")*$)");
Matcher matcher = pattern.matcher(highlightTerm);
StringBuilder builder = new StringBuilder();
int i = 0;
while (matcher.find()) {
String replacement = "\\" matcher.group(1);
builder.append(highlightTerm, i, matcher.start());
builder.append(replacement);
i = matcher.end();
}
builder.append(highlightTerm.substring(i));
highlightTerm = builder.toString();
//rest of your code
highlightTerm = highlightTerm.replaceAll("[\"]", "\\\"");
highlightTerm = highlightTerm.trim();
System.out.println(highlightTerm);
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