我在一個變數中有這樣的json資料,這里的資料如何一一使用。
我想這樣使用
開始 : 07.00 - 結束 : 22.00
Padding(
padding: const EdgeInsets.only(left: 6, top:2,right: 5,bottom:5),
child: Align(
alignment: Alignment.centerLeft,
child: Container(
child: Text(widget.company.worktime.toString(),style: TextStyle(fontSize: 16),),
),
),
),
結果;
[{"start":"07:00","end":"22:00","close":0},
{"start":"07:00","end":"22:00", "close":0},
{"start":"07:00","end":"22:00","close":0},
{"start":"07:00","end": "22:00","close":0},
{"start":"07:00","end":"22:00","close":0},
{"start":"07:00 ","end":"22:00","close":0},
{"start":"07:00","end":"22:00","close":0}]
uj5u.com熱心網友回復:
創建Worktime模型/資料類
class Worktime {
String? start;
String? end;
int? close;
Worktime({this.start, this.end, this.close});
Worktime.fromJson(Map<String, dynamic> json) {
start = json['start'];
end = json['end'];
close = json['close'];
}
Map<String, dynamic> toJson() {
final Map<String, dynamic> data = {};
data['start'] = start;
data['end'] = end;
data['close'] = close;
return data;
}
}
創建一個json串列資料決議器方法
List<Worktime> wrktimesFromJson(String str) =>
List<Worktime>.from(jsonDecode(str).map((x) => Worktime.fromJson(x)));
如果您的串列資料很大并且您需要更好的性能,請嘗試使用ListView.builder小部件,否則用于簡單的用例/小資料集使用Column with SingleChildScrollView。
對于 ListView.builder:
class _MyHomePageState extends State<MyHomePage> {
List<Worktime> worktimes = [];
@override
void initState() {
worktimes = wrktimesFromJson(widget.company.worktime.toString());
super.initState();
}
@override
Widget build(BuildContext context) {
return Scaffold(
appBar: AppBar(
title: Text(widget.title),
),
body: Padding(
padding: const EdgeInsets.only(left: 6, top: 2, right: 5, bottom: 5),
child: ListView.builder(
itemCount: worktimes.length,
itemBuilder: (BuildContext context, int index) {
var worktime = worktimes[index];
return Text(
"Start : ${worktime.start} - End : ${worktime.end}",
style: const TextStyle(fontSize: 16),
);
},
),
),
);
}
}
對于具有 SingleChildScrollView 的列:
class _MyHomePageState extends State<MyHomePage> {
List<Worktime> worktimes = [];
@override
void initState() {
worktimes = wrktimesFromJson(widget.company.worktime.toString());
super.initState();
}
@override
Widget build(BuildContext context) {
return Scaffold(
appBar: AppBar(
title: Text(widget.title),
),
body: SingleChildScrollView(
child: Padding(
padding: const EdgeInsets.only(left: 6, top: 2, right: 5, bottom: 5),
child: Column(
children: worktimes.map((worktime) {
return Text(
"Start : ${worktime.start} - End : ${worktime.end}",
style: const TextStyle(fontSize: 16),
);
}).toList(),
),
),
),
);
}
}
uj5u.com熱心網友回復:
需要最少的代碼來確定。但如果 json 資料包含在陣列中,則可以呼叫索引資料
或者可以使用這個 https://api.flutter.dev/flutter/widgets/ListView-class.html
轉載請註明出處,本文鏈接:https://www.uj5u.com/yidong/452967.html
