我有一個包含鍵的字典,同時該鍵包含某個整數串列。我想構建一個字典,將值顯示為鍵,而這個新字典的值將是包含先前值的先前鍵的串列。例如,我有:
turns
{'Monday_2022_03_14': [25, 17, 2, 32, 43, 40, 23, 7, 19, 16],
'Tuesday_2022_03_15': [33, 10, 16, 31, 25, 22, 43, 41, 21, 28, 3, 30, 29],
'Wednesday_2022_03_16': [19, 27, 40, 3, 9, 2, 14, 21, 44, 17],
'Thursday_2022_03_17': [16, 23, 1, 30, 29, 44, 5, 42, 27, 19],
'Friday_2022_03_18': [6, 17, 2, 29, 27, 41, 44, 5, 40, 42]}
例如,我想有:
{1:['Thursday_2022_03_17'],
2:['Monday_2022_03_14','Wednesday_2022_03_16','Friday_2022_03_18'],
3:['Tuesday_2022_03_15','Wednesday_2022_03_16],
...} #and so on
我嘗試在回圈中實作下一個解決方案(我在Get key by value in dictionary中找到了它),但后來我意識到這只能在只有一個值的鍵的字典中作業,而不是像我的串列:
list(turns.keys())[list(turns.values()).index(16)]
---------------------------------------------------------------------------
ValueError Traceback (most recent call last)
~\AppData\Local\Temp/ipykernel_19168/930684082.py in <module>
----> 1 list(turns.keys())[list(turns.values()).index(16)]
ValueError: 16 is not in list
如果你不提供回圈解決方案也沒關系,我可以實作它,但我需要幫助來按值獲取鍵名(如上面的行),但專注于串列而不是簡單值。
謝謝大家。
uj5u.com熱心網友回復:
一種方法是使用dict.setdefault和迭代串列:
out = {}
for k, lst in turns.items():
for v in lst:
out.setdefault(v, []).append(k)
然后,如果您希望字典按鍵排序,您可以使用sorted:
out = {k: out[k] for k in sorted(out)}
輸出:
{1: ['Thursday_2022_03_17'],
2: ['Monday_2022_03_14', 'Wednesday_2022_03_16', 'Friday_2022_03_18'],
3: ['Tuesday_2022_03_15', 'Wednesday_2022_03_16'],
5: ['Thursday_2022_03_17', 'Friday_2022_03_18'],
6: ['Friday_2022_03_18'],
7: ['Monday_2022_03_14'],
9: ['Wednesday_2022_03_16'],
10: ['Tuesday_2022_03_15'],
14: ['Wednesday_2022_03_16'],
16: ['Monday_2022_03_14', 'Tuesday_2022_03_15', 'Thursday_2022_03_17'],
17: ['Monday_2022_03_14', 'Wednesday_2022_03_16', 'Friday_2022_03_18'],
19: ['Monday_2022_03_14', 'Wednesday_2022_03_16', 'Thursday_2022_03_17'],
21: ['Tuesday_2022_03_15', 'Wednesday_2022_03_16'],
22: ['Tuesday_2022_03_15'],
23: ['Monday_2022_03_14', 'Thursday_2022_03_17'],
25: ['Monday_2022_03_14', 'Tuesday_2022_03_15'],
27: ['Wednesday_2022_03_16', 'Thursday_2022_03_17', 'Friday_2022_03_18'],
28: ['Tuesday_2022_03_15'],
29: ['Tuesday_2022_03_15', 'Thursday_2022_03_17', 'Friday_2022_03_18'],
30: ['Tuesday_2022_03_15', 'Thursday_2022_03_17'],
31: ['Tuesday_2022_03_15'],
32: ['Monday_2022_03_14'],
33: ['Tuesday_2022_03_15'],
40: ['Monday_2022_03_14', 'Wednesday_2022_03_16', 'Friday_2022_03_18'],
41: ['Tuesday_2022_03_15', 'Friday_2022_03_18'],
42: ['Thursday_2022_03_17', 'Friday_2022_03_18'],
43: ['Monday_2022_03_14', 'Tuesday_2022_03_15'],
44: ['Wednesday_2022_03_16', 'Thursday_2022_03_17', 'Friday_2022_03_18']}
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