我有下表及其樣本資料如下,
------------------ ------- -------- --------------------- -------
| PhoneCode | SeqID | Active | Token | CUSID |
------------------ ------- -------- --------------------- -------
| e29a5e1c695352b8 | 3898 | I | JYN8CYRVzaKWL-l_K | 50002 |
------------------ ------- -------- --------------------- -------
| e29a5e1c695352b8 | 3900 | I | JYN8CYRVzaKWL-l_K | 50002 |
------------------ ------- -------- --------------------- -------
| 741fb28bc72183e3 | 3899 | I | RU3ReKEw0yin9LxZWCO | 50002 |
------------------ ------- -------- --------------------- -------
| 741fb28bc72183e4 | 3901 | A | RU3ReKEw0yin9LxZWCO | 50002 |
------------------ ------- -------- --------------------- -------
我需要PhoneCode與 latest區別開來SeqID。所以我嘗試了以下查詢。
SELECT UD.PHONECODE, UD.SeqID, UD.ACTIVE, UD.Token
FROM DEVICE UD
WHERE UD.CUSID = '50002' AND UD.ACTIVE = 'I'
GROUP BY PHONECODE
但它會出錯。如何檢索以下輸出?
------------------ ------- -------- --------------------- -------
| PhoneCode | SeqID | Active | Token | CUSID |
------------------ ------- -------- --------------------- -------
| e29a5e1c695352b8 | 3900 | I | JYN8CYRVzaKWL-l_K | 50002 |
------------------ ------- -------- --------------------- -------
| 741fb28bc72183e3 | 3899 | I | RU3ReKEw0yin9LxZWCO | 50002 |
------------------ ------- -------- --------------------- -------
uj5u.com熱心網友回復:
您可以在沒有GROUP BY和沒有自連接的情況下執行此操作:
SELECT PHONECODE,
SeqID,
ACTIVE,
Token
FROM (
SELECT d.*,
ROW_NUMBER() OVER (PARTITION BY phonecode ORDER BY seqid DESC) AS rn
FROM device d
WHERE cusid = 50002
AND active = 'I'
)
WHERE rn = 1;
或者,如果你想使用,GROUP BY那么你也可以使用KEEP:
SELECT PHONECODE,
MAX(SeqID) AS seqid,
MAX(ACTIVE) KEEP (DENSE_RANK LAST ORDER BY SeqID) AS active,
MAX(Token) KEEP (DENSE_RANK LAST ORDER BY SeqID) AS token
FROM device
WHERE cusid = 50002
AND active = 'I'
GROUP BY phonecode;
其中,對于樣本資料:
CREATE TABLE device (PhoneCode, SeqID, Active, Token, CUSID ) AS
SELECT 'e29a5e1c695352b8', 3898, 'I', 'JYN8CYRVzaKWL-l_K', 50002 FROM DUAL UNION ALL
SELECT 'e29a5e1c695352b8', 3900, 'I', 'JYN8CYRVzaKWL-l_K', 50002 FROM DUAL UNION ALL
SELECT '741fb28bc72183e3', 3899, 'I', 'RU3ReKEw0yin9LxZWCO', 50002 FROM DUAL UNION ALL
SELECT '741fb28bc72183e4', 3901, 'A', 'RU3ReKEw0yin9LxZWCO', 50002 FROM DUAL;
兩個輸出:
電話號碼 序列號 積極的 代幣 741fb28bc72183e3 3899 一世 RU3ReKEw0yin9LxZWCO e29a5e1c695352b8 3900 一世 JYN8CYRVzaKWL-l_K
db<>在這里擺弄
uj5u.com熱心網友回復:
一個簡單的子查詢怎么樣
SELECT UD.PHONECODE, UD.SeqID, UD.ACTIVE, UD.Token
FROM device ud
WHERE (UD.PHONECODE, UD.SeqID) IN (
SELECT PHONECODE, MAX(SeqID)
FROM device
WHERE CUSID = '50002' AND ACTIVE = 'I'
GROUP BY PHONECODE
)
uj5u.com熱心網友回復:
您可以使用MAX()并加入:
SELECT UD.PHONECODE, UD.ACTIVE, UD.Token, UD.SeqID
FROM DEVICE UD
INNER JOIN (
SELECT PHONECODE, MAX(SeqID) as SEQID
FROM DEVICE
WHERE CUSID = '50002' AND ACTIVE = 'I'
GROUP BY PHONECODE
) T2 ON UD.PHONECODE = T2.PHONECODE AND UD.SEQID = T2.SEQID
uj5u.com熱心網友回復:
以下查詢將起作用:
select phonecode,seqid,active,token,cusid
from
(
select * , row_number() over(partition by phonecode order by seqid desc) as rownum
from device
where cusid = 50002 and active = 'I'
) as t1
where rownum = 1
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