我正在嘗試撰寫一些代碼以通過 xpath 將節點插入到通用配置中。
通常我正在撰寫.Net應用程式，但現在我需要在nodejs上撰寫工具，輸入腳本
我不明白如何正確撰寫如何制作**childNodes [0]**所以我可以呼叫**appendChild **？
import {DOMParser as dom} from "xmldom";
import * as xpath from "xpath";
export default class FileJob extends BaseJob {
async execute(settings: JobSettings) {
this.poke('C:\\Temp\\LocalCache\\Config.xml','/Root','<DB-Connection id="development" database="development"/>');
}
private poke(path:fs.PathLike,pathToNode:string, node : string)
{
const file = fs.readFileSync(path,'utf-8');
var doc = new dom().parseFromString(file);
var tempDoc = new dom().parseFromString(node);
var importedNode = doc.importNode(tempDoc.documentElement, true);
var childNodes = xpath.select(pathToNode, doc);
if (childNodes[0]!==undefined)
{
//What to do here?
//Property 'appendChild' does not exist on type 'SelectedValue'.
//Property 'appendChild' does not exist on type 'string'.
childNodes[0].appendChild(importedNode);
fs.writeFileSync(path,doc.toString());
}
}
}
uj5u.com熱心網友回復：
我又傻又年輕。
這是必要的。
import {DOMParser as dom} from "xmldom";
import * as xpath from "xpath";
export default class FileJob extends BaseJob {
async execute(settings: JobSettings) {
this.poke('C:\\Temp\\LocalCache\\Config.xml','/Root','<DB-Connection id="development" database="development"/>');
}
private poke(path:fs.PathLike,pathToNode:string, node : string)
{
const file = fs.readFileSync(path,'utf-8');
var doc = new dom().parseFromString(file);
var tempDoc = new dom().parseFromString(node);
var importedNode = doc.importNode(tempDoc.documentElement, true);
var childNodes = xpath.select(pathToNode, doc);
if (childNodes[0]!==undefined)
{
let currentNode = childNodes[0] as Node;
currentNode.appendChild(importedNode);
fs.writeFileSync(path,doc.toString());
}
}
}
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