我正在嘗試加載示例 BPF 過濾器,但出現以下錯誤:
Prog section 'classifier' rejected: Permission denied (13)!
- Type: 3
- Instructions: 58 (0 over limit)
- License: GPL
Verifier analysis:
0: (bf) r6 = r1
1: (61) r2 = *(u32 *)(r6 80)
2: (61) r1 = *(u32 *)(r6 76)
3: (bf) r3 = r1
4: (07) r3 = 14
5: (2d) if r3 > r2 goto pc 50
R1_w=pkt(id=0,off=0,r=14,imm=0) R2_w=pkt_end(id=0,off=0,imm=0) R3_w=pkt(id=0,off=14,r=14,imm=0) R6_w=ctx(id=0,off=0,imm=0) R10=fp0
6: (bf) r3 = r1
7: (07) r3 = 15
8: (2d) if r3 > r2 goto pc 47
R1_w=pkt(id=0,off=0,r=15,imm=0) R2_w=pkt_end(id=0,off=0,imm=0) R3_w=pkt(id=0,off=15,r=15,imm=0) R6_w=ctx(id=0,off=0,imm=0) R10=fp0
9: (71) r3 = *(u8 *)(r1 13)
10: (67) r3 <<= 8
11: (71) r4 = *(u8 *)(r1 12)
12: (4f) r3 |= r4
13: (57) r3 &= 65535
14: (55) if r3 != 0x8 goto pc 41
R1=pkt(id=0,off=0,r=15,imm=0) R2=pkt_end(id=0,off=0,imm=0) R3=inv8 R4=inv(id=0,umax_value=255,var_off=(0x0; 0xff)) R6=ctx(id=0,off=0,imm=0) R10=fp0
15: (71) r3 = *(u8 *)(r1 23)
invalid access to packet, off=23 size=1, R1(id=0,off=23,r=15)
R1 offset is outside of the packet
processed 16 insns (limit 1000000) max_states_per_insn 0 total_states 1 peak_states 1 mark_read 1
Error fetching program/map!
Unable to load program
我正在使用以下命令來編譯和加載:
# clang -O2 -Wall -I/usr/include/x86_64-linux-gnu -target bpf -c classifier.c -o classifier.o
# tc filter add dev wlp0s20f3 ingress bpf obj classifier.o flowid 0:
如果我注釋掉這一行trace_printk("Yes! It is HTTP!\n"); 它加載。trace_printk() 是一個宏,我也嘗試直接呼叫 bpf_trace_printk() 但結果相同。
#include <linux/if_ether.h>
#include <linux/tcp.h>
#include <linux/ip.h>
#include <linux/in.h>
#include <linux/bpf.h>
#include <linux/pkt_cls.h>
//#include <bpf/bpf_helpers.h>
#define SEC(NAME) __attribute__((section(NAME), used))
#if __BYTE_ORDER__ == __ORDER_LITTLE_ENDIAN__
#define __bpf_htons(x) __builtin_bswap16(x)
#define __bpf_constant_htons(x) ___constant_swab16(x)
#elif __BYTE_ORDER__ == __ORDER_BIG_ENDIAN__
#define __bpf_htons(x) (x)
#define __bpf_constant_htons(x) (x)
#else
#error "Fix your compiler's __BYTE_ORDER__?!"
#endif
#define bpf_htons(x) \
(__builtin_constant_p(x) ? __bpf_constant_htons(x) : __bpf_htons(x))
static long (*bpf_trace_printk)(const char *fmt, __u32 fmt_size,
...) = (void *)BPF_FUNC_trace_printk;
#define trace_printk(fmt, ...) \
do { \
char _fmt[] = fmt; \
bpf_trace_printk(_fmt, sizeof(_fmt), ##__VA_ARGS__); \
} while (0)
static inline int is_http(struct __sk_buff *skb, __u64 nh_off);
unsigned long long load_byte(void *skb,
unsigned long long off) asm("llvm.bpf.load.byte");
SEC("classifier")
static inline int classification(struct __sk_buff *skb) {
void *data_end = (void *)(long)skb->data_end;
void *data = (void *)(long)skb->data;
struct ethhdr *eth = data;
__u16 h_proto;
__u64 nh_off = 0;
nh_off = sizeof(*eth);
if (data nh_off > data_end) {
return TC_ACT_OK;
}
h_proto = eth->h_proto;
if (h_proto == bpf_htons(ETH_P_IP)) {
if (is_http(skb, nh_off) == 1) {
trace_printk("Yes! It is HTTP!\n"); // (ERROR)
}
}
return TC_ACT_OK;
}
static inline int is_http(struct __sk_buff *skb, __u64 nh_off) {
void *data_end = (void *)(long)skb->data_end;
void *data = (void *)(long)skb->data;
struct iphdr *iph = data nh_off;
if ((void*)iph 1 > data_end) {
return 0;
}
if (iph->protocol != IPPROTO_TCP) {
return 0;
}
__u32 tcp_hlen = 0;
__u32 ip_hlen = 0;
__u32 poffset = 0;
__u32 plength = 0;
__u32 ip_total_length = iph->tot_len;
ip_hlen = iph->ihl << 2;
if (ip_hlen < sizeof(*iph)) {
return 0;
}
struct tcphdr *tcph = data nh_off sizeof(*iph);
if ((void*)tcph 1 > data_end) {
return 0;
}
tcp_hlen = tcph->doff << 2;
poffset = ETH_HLEN ip_hlen tcp_hlen;
plength = ip_total_length - ip_hlen - tcp_hlen;
if (plength >= 7) {
unsigned long p[7];
int i = 0;
for (i = 0; i < 7; i ) {
p[i] = load_byte(skb, poffset i);
}
if ((p[0] == 'H') && (p[1] == 'T') && (p[2] == 'T') && (p[3] == 'P')) {
return 1;
}
}
return 0;
}
char _license[] SEC("license") = "GPL";
uj5u.com熱心網友回復:
trace_printk實際上不是這里的問題。看起來就是這樣,因為一旦您評論了該陳述句,驗證程式就會優化對is_http();的呼叫。它不再需要了。
這是怎么回事?
驗證程式拒絕您的 BPF 程式并出現以下錯誤:
invalid access to packet, off=23 size=1, R1(id=0,off=23,r=15)
R1 offset is outside of the packet
這意味著您正在嘗試訪問偏移量 23 處的資料包,即使您僅驗證它是 15 個位元組長。
哪里的bug?
我懷疑錯誤在這些行中:
if ((void*)iph 1 > data_end) {
return 0;
}
在這里,您檢查的data_end是大于或等于iph加一個位元組。我們可以在驗證器輸出中看到它:
3: (bf) r3 = r1
4: (07) r3 = 14
5: (2d) if r3 > r2 goto pc 50
R1_w=pkt(id=0,off=0,r=14,imm=0) R2_w=pkt_end(id=0,off=0,imm=0) R3_w=pkt(id=0,off=14,r=14,imm=0) R6_w=ctx(id=0,off=0,imm=0) R10=fp0
6: (bf) r3 = r1
7: (07) r3 = 15
8: (2d) if r3 > r2 goto pc 47
R1_w=pkt(id=0,off=0,r=15,imm=0) R2_w=pkt_end(id=0,off=0,imm=0) R3_w=pkt(id=0,off=15,r=15,imm=0) R6_w=ctx(id=0,off=0,imm=0) R10=fp0
第一個比較是 for data nh_off > data_end,第二個是 for (void*)iph 1 > data_end。如您所見,差異只有一個位元組。
解決方法是什么?
我想你想要:
if ((void*)(iph 1) > data_end) {
return 0;
}
下一個資料包邊界檢查(tcp)也是如此。
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