我有一組通過 LazyVgrid 傳遞的影像。
我想知道如何將 NavigationLink 分配給存盤在陣列中的影像名稱，單擊 icon1 導航到 page1，等等所有 8。
------ 斯威夫特用戶界面 --------
import SwiftUI
struct Grid: View {
var images: [String] = ["icon1", "icon2", "icon3", "icon4",
"icon5", "icon6", "icon7","icon8"]
var columnGrid: [GridItem] = [GridItem(.flexible(), spacing: 25), GridItem(.flexible(), spacing: 25)]
var body: some View {
LazyVGrid(columns: columnGrid, spacing: 50) {
ForEach(images, id:\.self) { image in
Image(image)
.resizable()
.scaledToFill()
.frame(width: (UIScreen.main.bounds.width / 2.75 ) - 1,
height: (UIScreen.main.bounds.width / 2.75 ) - 1)
.clipped()
.cornerRadius(25)
}
}
}
}
uj5u.com熱心網友回復：
對于這樣的場合，我更喜歡一個包含所有相關資訊的列舉。您也可以使用結構來執行此操作，其背后的原因保持不變。
enum ImageEnum: String, CaseIterable{ //Please find a better name ;)
case image1, image2
var imageName: String{ // get the assetname of the image
switch self{
case .image1:
return "test"
case .image2:
return "test2"
}
}
@ViewBuilder
var detailView: some View{ // create the view here, if you need to add
switch self{ // paramaters use a function or associated
case .image1: // values for your enum cases
TestView1()
case .image2:
TestView2()
}
}
}
struct TestView1: View{
var body: some View{
Text("test1")
}
}
struct TestView2: View{
var body: some View{
Text("test2")
}
}
而你的Grid觀點：
struct Grid: View {
var columnGrid: [GridItem] = [GridItem(.flexible(), spacing: 25), GridItem(.flexible(), spacing: 25)]
var body: some View {
NavigationView{ // Add the NavigationView
LazyVGrid(columns: columnGrid, spacing: 50) {
ForEach(ImageEnum.allCases, id:\.self) { imageEnum in // Itterate over all enum cases
NavigationLink(destination: imageEnum.detailView){ // get detailview here
Image(imageEnum.imageName) // get image assset name here
.resizable()
.scaledToFill()
.clipped()
.cornerRadius(25)
}
}
}
}
}
}
結果：
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