我想像這樣向用戶顯示一個完整的句子：
相差 5 天 3 小時 16 分鐘 10 秒和 150 微秒。
但排除零項。
例如：91 天，23:00:00 列印為：
差別是 91 天和 23 小時。
我現在能想到的唯一方法是創建一堆if宣告，正如我在下面發布的那樣。我認為這可能過于復雜，我希望有一種更簡單的方法。
# prompts the user to enter the date following the order
d1 = input('Please enter the date time (YYYY-mm-dd hour:minute:second:microsecond): ')
m_d1 = datetime.strptime(d1, '%Y-%m-%d %H:%M:%S:%f') # a datetime variable with the entered info
# prompts the user to enter another date following the order
d2 = input('Please enter the date time (YYYY-mm-dd hour:minute:second:microsecond): ')
m_d2 = datetime.strptime(d2, '%Y-%m-%d %H:%M:%S:%f') # another datetime variable with the entered info
if m_d1 > m_d2:
result_date = m_d1 - m_d2
else:
result_date = m_d2 - m_d1
# total difference in number of days with fraction
difference_days = result_date.total_seconds() / timedelta(days=1).total_seconds()
# total difference in number of hours with fraction
difference_hours = result_date.total_seconds() / timedelta(hours=1).total_seconds()
# total difference in number of minutes with fraction
difference_minutes = result_date.total_seconds() / timedelta(minutes=1).total_seconds()
# total difference in number of seconds with fraction
difference_seconds = result_date.total_seconds()
# total difference in number of microseconds with fraction
difference_microseconds = result_date.total_seconds() / timedelta(microseconds=1).total_seconds()
# now, A complete sentence that breaks everything down to the
# correct units and excluding any 0s.
if difference_days.is_integer():
print(f'The difference is {int(difference_days)} days.')
else:
hours = (Decimal(difference_days) - int(difference_days)) * 24
if difference_hours.is_integer():
if difference_days > 1:
print(f'The difference is {int(difference_days)} days and {int(hours)} hours.')
else:
print(f'The difference is {int(hours)} hours.')
else:
minutes = (hours - int(hours)) * 60
if difference_minutes.is_integer():
if difference_days < 1 and hours < 1:
print(f'The difference is {int(minutes)} minutes.')
elif difference_days > 1 and hours < 1:
print(f'The difference is {int(difference_days)} days and {int(minutes)} minutes.')
else:
print(
f'The difference is {int(difference_days)} days, {int(hours)} hours, and {int(minutes)} minutes.')
else:
seconds = (minutes - int(minutes)) * 60
if difference_seconds.is_integer():
if difference_days < 1 and hours < 1 and minutes < 1:
print(f'The difference is {int(seconds)} seconds.')
elif difference_days > 1 and hours < 1 and minutes < 1:
print(f'The difference is {int(difference_days)} days and {int(seconds)} seconds.')
elif difference_days < 1 and hours > 1 and minutes < 1:
print(f'The difference is {int(hours)} hours and {int(seconds)} seconds.')
else:
# ... other code
uj5u.com熱心網友回復：
使用 DRY（不要重復自己）原則。您不必為每個時間單位重寫代碼，因為它是相同的：
non_zero_counts = {}
rest = result_date
for duration in ["days", "hours", "minutes", "seconds", "microseconds"]:
td = timedelta(**{duration: 1})
count = int(rest / td)
rest = rest - count * td
if count:
non_zero_counts[duration] = count
結果是一個字典：
non_zero_counts
Out[27]: {'days': 31, 'hours': 3, 'seconds': 34, 'microseconds': 50000}
我將處理所有特殊情況，以使語言正確由您決定。隨意編輯此答案以添加您形成句子本身的解決方案。
編輯
造句：
if non_zero_counts:
result = ', '.join(f'{value} {key}' for key, value in
non_zero_counts.items())
print(f'The difference is {result}')
else:
print('The two dates are the same.')
輸入：
Please enter the date time (YYYY-mm-dd hour:minute:second:microsecond): 2022-08-04 15:30:20:12470
Please enter the date time (YYYY-mm-dd hour:minute:second:microsecond): 2022-09-08 12:44:33:12348
輸出：
The difference is 34 days, 21 hours, 14 minutes, 12 seconds, 998780 microseconds
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