用字母和數字在字典串列中排序

我有一個要排序的字典串列。這是我到目前為止所擁有的：

output_list = [{'mac': '0123.4567.89ab', 'port': 'Gi1/0/10'},
               {'mac': '0123.4567.89ab', 'port': 'Gi1/0/1'},
               {'mac': '0123.4567.89ab', 'port': 'Gi1/0/5'},
               {'mac': '0123.4567.89ab', 'port': 'Gi1/0/48'},
               {'mac': '0123.4567.89ab', 'port': 'Gi2/0/1'},
               {'mac': '0123.4567.89ab', 'port': 'Gi1/0/6'},
               {'mac': '0123.4567.89ab', 'port': 'Gi2/0/4'},
               {'mac': '0123.4567.89ab', 'port': 'Gi2/0/13'},
               {'mac': '0123.4567.89ab', 'port': 'Gi8/0/9'},
               {'mac': '0123.4567.89ab', 'port': 'Gi8/0/8'},
               {'mac': '0123.4567.89ab', 'port': 'Te1/1/1'}]

mac_list = sorted(output_list, key=lambda d: "/".join([x for x in d['port'].split("/")]))

pprint(mac_list)

但是，它并沒有按照我想要的方式對字典進行排序。

"C:\Program Files\Python310\python.exe" "C:/Scripts/Python/test1.py"
[{'mac': '0123.4567.89ab', 'port': 'Gi1/0/1'},
 {'mac': '0123.4567.89ab', 'port': 'Gi1/0/10'},
 {'mac': '0123.4567.89ab', 'port': 'Gi1/0/48'},
 {'mac': '0123.4567.89ab', 'port': 'Gi1/0/5'},
 {'mac': '0123.4567.89ab', 'port': 'Gi1/0/6'},
 {'mac': '0123.4567.89ab', 'port': 'Gi2/0/1'},
 {'mac': '0123.4567.89ab', 'port': 'Gi2/0/13'},
 {'mac': '0123.4567.89ab', 'port': 'Gi2/0/4'},
 {'mac': '0123.4567.89ab', 'port': 'Gi8/0/8'},
 {'mac': '0123.4567.89ab', 'port': 'Gi8/0/9'},
 {'mac': '0123.4567.89ab', 'port': 'Te1/1/1'}]

Process finished with exit code 0

我怎樣才能讓它排序它看起來像這樣：

[{'mac': '0123.4567.89ab', 'port': 'Gi1/0/1'},
 {'mac': '0123.4567.89ab', 'port': 'Gi1/0/5'},
 {'mac': '0123.4567.89ab', 'port': 'Gi1/0/6'},
 {'mac': '0123.4567.89ab', 'port': 'Gi1/0/10'},
 {'mac': '0123.4567.89ab', 'port': 'Gi1/0/48'},
 {'mac': '0123.4567.89ab', 'port': 'Gi2/0/1'},
 {'mac': '0123.4567.89ab', 'port': 'Gi2/0/4'},
 {'mac': '0123.4567.89ab', 'port': 'Gi2/0/13'},
 {'mac': '0123.4567.89ab', 'port': 'Gi8/0/8'},
 {'mac': '0123.4567.89ab', 'port': 'Gi8/0/9'},
 {'mac': '0123.4567.89ab', 'port': 'Te1/1/1'}]

uj5u.com熱心網友回復：

嘗試：

out = sorted(
    output_list,
    key=lambda d: (d["port"][:2], *map(int, d["port"][2:].split("/"))),
)

print(out)

印刷：

[
    {"mac": "0123.4567.89ab", "port": "Gi1/0/1"},
    {"mac": "0123.4567.89ab", "port": "Gi1/0/5"},
    {"mac": "0123.4567.89ab", "port": "Gi1/0/6"},
    {"mac": "0123.4567.89ab", "port": "Gi1/0/10"},
    {"mac": "0123.4567.89ab", "port": "Gi1/0/48"},
    {"mac": "0123.4567.89ab", "port": "Gi2/0/1"},
    {"mac": "0123.4567.89ab", "port": "Gi2/0/4"},
    {"mac": "0123.4567.89ab", "port": "Gi2/0/13"},
    {"mac": "0123.4567.89ab", "port": "Gi8/0/8"},
    {"mac": "0123.4567.89ab", "port": "Gi8/0/9"},
    {"mac": "0123.4567.89ab", "port": "Te1/1/1"},
]

筆記：

(d["port"][:2], *map(int, d["port"][2:].split("/")))將在表單('Gi', 1, 0, 48)等中創建元組。然后該sorted()函式將根據這些元組進行排序。

uj5u.com熱心網友回復：

似乎您正在尋找人類/自然排序。這個答案很好地涵蓋了它。

使用該natural_keys答案中的函式，然后可以將埠字串直接傳遞給定義的函式，如下所示：

output_list.sort(key=lambda d: natural_keys(d["port"]))

uj5u.com熱心網友回復：

嘗試這個：

mac_list = sorted(output_list, key=lambda d: tuple(int(x) if x.isdigit() else x for x in d['port'].split("/")))

這會將數字字串轉換為產生int的值的子字串中的port值，split()并保持非數字字串不變，并且基于結果tuple值的排序將為您提供所需的輸出。

標籤：Python 列表 排序 字典

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