將文本框中輸入的值保存到xml檔案中

我是 XML 新手，我嘗試創建一個視窗表單，用于收集每位教師、學生、操作員和技術人員的人數、姓名、姓氏和等級。但是這段代碼會很長。您對在 c# 上創建此 XML 有什么建議嗎？資訊將從每個員工的人數、姓名、姓氏和等級的 4 個文本框中獲取。此外，描述將從文本框中獲取。

<Simulator>
    <Flight ID="1" Description="rainy_day">
      <Instructor Num="14213124">
        <Name>Jack</Name>
        <Surname>Sparrow</Surname>
        <Rank>General</Rank>
      </Instructor>
      <Student Num="56475679">
        <Name>Adam</Name>
        <Surname>Black</Surname>
        <Rank>Lieutenant</Rank>
      </Student>
      <Operator Num="75846474">
        <Name>Gabriel</Name>
        <Surname>Red</Surname>
        <Rank>Op</Rank>
      </Operator>
      <Technician Num="85425484">
        <Name>Samuel</Name>
        <Surname>Long</Surname>
        <Rank>Tec</Rank>
      </Technician>
    </Flight>
</Simulator>

這是我試過的代碼。如果我為每個員工一次又一次地寫這個會很長

XmlDeclaration xmlDeclaration = xmlDoc.CreateXmlDeclaration("1.0", "UTF-8", "yes");
                XmlElement rootNode = xmlDoc.DocumentElement;
                xmlDoc.InsertAfter(xmlDeclaration, rootNode);

                XmlNode parentNode = xmlDoc.CreateElement("Users");
                XmlNode subNode = xmlDoc.CreateElement("Instructor");

                XmlAttribute numAtt = xmlDoc.CreateAttribute("Num");
                numAtt.Value = num.ToString();
                XmlAttribute nameAtt = xmlDoc.CreateAttribute("Name");
                nameAtt.Value = name;
                XmlAttribute surnameAtt = xmlDoc.CreateAttribute("Surname");
                surnameAtt.Value = surname;
                XmlAttribute rankAtt = xmlDoc.CreateAttribute("Rank");
                rankAtt.Value = rank;

                subNode.Attributes.Append(numAtt);
                subNode.Attributes.Append(nameAtt);
                subNode.Attributes.Append(surnameAtt);
                subNode.Attributes.Append(rankAtt);

                xmlDoc.AppendChild(parentNode);
                parentNode.AppendChild(subNode);

檢查 id 部分

var userElements = xDoc.Descendants("Flight").ToList();
            string lastID = userElements.Select(x => (x.Attribute("ID").Value))
                  .OrderByDescending(x => x)
                  .First()
                  .ToString();
            int lastID_int = Int16.Parse(lastID)   1;
            if (lastID_int <= 0)
                lastID_int = 0;
            string current = lastID_int.ToString();
            Simulator sim = new Simulator(current, textbox_description.Text);

uj5u.com熱心網友回復：

這是使用 XML Linq 的類：

   public class Simulator
    {
        XDocument doc = null;
        public Simulator(string filename)
        {
            doc = XDocument.Load(filename);
        }
        public Simulator(string id, string description)
        {
            string ident = "<?xml version=\"1.0\" encoding=\"utf-8\"?><Simulator></Simulator>";
            doc = XDocument.Parse(ident);
            XElement flight = new XElement("Flight", new object[] {
                new XAttribute("ID", id),
                new XAttribute("Description", description)
            });

            doc.Root.Add(flight);
        }
        public string AddUser(string flightID, string role, string number, string name, string surname, string rank)
        {
            XElement flight = doc.Descendants("Flight").Where(x => (string)x.Attribute("ID") == flightID).FirstOrDefault();

            if (flight != null)
            {
                XElement user = new XElement(role, new object[] {
                    new XAttribute("Num", number),
                    new XElement("Name", name),
                    new XElement ("Surname", surname),
                    new XElement("Rank", rank)
                });
                flight.Add(user);
                return "GOOD";
            }
            else
            {
                return "Flight ID doesn't exist";
            }
        }
        public string AddFlight(string flightID, string description)
        {
            XElement flight = doc.Descendants("Flight").Where(x => (string)x.Attribute("ID") == flightID).FirstOrDefault();
            if (flight == null)
            {
                flight = new XElement("Flight", new object[] {
                    new XAttribute("ID", flightID),
                    new XAttribute("Description", description)
                });
                doc.Root.Add(flight);
                return "Good";
            }
            else
            {
                return "Flight ID already exists";
            }
        }
        public string AddErrors(string flightID, XElement errorLog)
        {
            XElement flight = doc.Descendants("Flight").Where(x => (string)x.Attribute("ID") == flightID).FirstOrDefault();
            if(flight == null)
            {
                return "Flight ID doesn't exist";
            }
            else
            {
                flight.Add(errorLog);
                return "GOOD";
            }

        }

        public void WriteXml(string filename)
        {
            doc.Save(filename);
        }
    }

uj5u.com熱心網友回復：

您可能應該使用xmlSerializer而不是嘗試手動創建 xml 樹。

這應該讓您為資料創建類，并讓序列化程式擔心將物件轉換為 xml：

public class Person{
    public string Num{get;set;}
    public string Name {get;set;}
    public string Surname {get;set;}
    public string Rank{get;set;}
}
public class Flight{
    public Person Instructor {get;set;}
    public Person Student {get;set;}
    ....
}

var serializer = new XmlSerializer(typeof(Flight));
var writer = new StreamWriter(filename);
serializer.Serialize(writer, myFlight);

這可能無法準確地為您提供所需的布局，但通常可以通過 attributes 控制。另請參閱Json .net以獲得更流行的 xml 替代方案。

標籤：C＃ xml 表格

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