我有一個格式如下的檔案。我已經完成了決議。我有代碼可以通過 switch-case 或 if() 查找每個鍵的出現。但我想找到一種更好的方法來做到這一點。這是我需要決議然后找到鍵的出現的訊息。我們可以看到每一行的訊息都被標記為“;”，可以認為是7列。第 2 列的元素稱為“名稱”。我們可以理解，如果一個名字出現在每一行上意味著它的出現應該增加。我想找到每個鍵名的總出現次數：AMD、其他...
09:00:15.390001;AMD;2837197;I;BUY;111;35.20
09:00:15.680001;AMD;2837197;C;BUY;111;35.20
09:00:16.040001;AMD;2837198;I;BUY;20;35.00
09:00:16.500001;AMD;2837196;C;BUY;1;35.10
09:00:16.860001;DVAM2;2837181;C;SELL;36;9.30
09:00:16.870001;AMD;2837198;C;BUY;20;35.00
09:00:17.310001;AMD;2837199;I;SELL;8;36.10
09:00:18.920001;AMD;2837200;I;SELL;9;36.10
09:00:19.190001;DVAM2;2837201;I;SELL;9;9.00
09:00:19.650001;AMD;2837202;I;SELL;160;35.90
09:00:19.940001;OTHER;2837180;C;BUY;7;18.40
09:00:19.960001;AMD;2837202;C;SELL;160;35.90
09:00:20.210001;AMD;2837199;C;SELL;8;36.10
09:00:20.550001;AMD;2837200;C;SELL;9;36.10
09:00:20.640001;AMD;2837203;I;BUY;4;35.70
09:00:21.400001;OTHER;2837204;I;BUY;6;18.20
09:00:21.460001;AMD;2837205;I;BUY;5;35.50
09:00:22.110001;AMD;2837203;A;BUY;4;35.70
09:00:22.350001;DVAM2;2837201;C;SELL;9;9.00
09:00:22.430001;OTHER;2837206;I;BUY;8;18.10
09:00:22.650001;TEST1;2837207;I;SELL;1;32.70
09:00:23.410001;AMD;2837208;I;SELL;9;36.40
09:00:23.420001;AMD;2837208;C;SELL;9;36.40
09:00:24.140001;AMD;2837205;C;BUY;5;35.50
09:00:24.980001;TEST0;2837182;C;SELL;76;23.20
09:00:25.310001;DVAM2;2837185;C;SELL;3;9.00
09:00:25.470001;AMD;2837203;C;BUY;4;35.70
09:00:25.470001;AMD;2837209;I;BUY;4;35.20
09:00:25.470001;OTHER;2837206;C;BUY;8;18.10
09:00:25.630001;TEST0;2837210;I;BUY;3;22.90
09:00:26.020001;AMD;2837209;C;BUY;4;35.20
09:00:26.480001;AMD;2837211;I;SELL;8;36.00
09:00:26.960001;AMD;2837211;C;SELL;8;36.00
09:00:27.060001;AMD;2837212;I;SELL;5;36.20
09:00:27.350001;AMD;2837213;I;BUY;9;35.30
09:00:27.690001;OTHER;2837204;C;BUY;6;18.20
09:00:27.960001;TEST4;2837214;I;SELL;9;16.20
這是我的代碼
// IManager.h
class inventory
{
public:
std::unordered_map<std::string, int64_t> orderCountPerDVAM1Symbol, orderCountPerDVAM2Symbol, orderCountPerOTHERSymbol;
}
//BManager.cpp
// Order count of each key, e.g. DVAM1 as you see in the attached photo will be increased no matter we seel or buy it.
int64_t inventory::orderCounts(std::string symbols)
{
if (sellHead != NULL && orderCountPerDVAM1Symbol.find(symbols) != orderCountPerDVAM1Symbol.end() && symbols == "DVAM1")
orderCountPerDVAM1Symbol[sellTail->symbol] ; // increment order count when selling
if (buyHead != NULL && orderCountPerDVAM1Symbol.find(symbols) != orderCountPerDVAM1Symbol.end() && symbols == "DVAM1")
orderCountPerDVAM1Symbol[buyTail->symbol] ; // increment order count when buying
return orderCountPerDVAM1Symbol[sellTail->symbol];
}
// main.cpp
struct messageData // Defining one row of message data
{
// Message Format: timestamp;symbol;order-id;operation;side;volume;price
std::string timestamp;
std::string symbol;
unsigned long long int orderid;
char operation;
char side;
unsigned long int volume;
float price;
};
int main(int argc, const char * argv[])
{
messageData inMsg;
std::ifstream messageStream("test1.txt"); //orders coding test developer.dat
std::ofstream logBook("_LogBook.txt", std::ios::out);
int64_t orderCountDVAM1, orderCountDVAM2, orderCountOther, orderCount0, orderCount1, orderCount2, orderCount3, orderCount4, orderCount5, orderCount6, orderCount7;
while (std::getline(messageStream, messageLine)) // Loop until last line of message stream
{
std::stringstream lineStream(messageLine); // Read each message line
std::cout << "Message row no." << messageRow << ":\n" << messageLine << '\n'; // For test purposes
cellID = 0; // cellID: 0(timestamp); 1(symbol); 2(order-id), 3(operation); 4(side); 5(volume); 6(price)
while (std::getline(lineStream, messageCell, ';') && cellID < 8) // Loop & Quality check until last cell of message line
{
....
cellID ;
}
if(messageTestPassed)
{
vol.push_back(inMsg.symbol);
}
// Next message line will be read from the stream and the cycle repeated.
messageRow ; // Increment message row number.
std::cout << '\n';
for (auto symbol : vol) {
orderCount = inventory.orderCounts(symbol);
std::cout << "\t\t\t\tTOTAL Order count = " << orderCount << '\n';
}
logBook << "\t\t\t\tTOTAL Order count = " << myLTOS(orderCount) << '\n';
logBook.close();
return 0;
}
問題是我得到了每個鍵的錯誤值。如在這張照片中 發現錯誤
Msg #1 09:00:00.440000;AMD;2837174;I;SELL;72;36.30
TOTAL AMD Order count =
Msg #2 09:00:00.690000;TEST8;2837175;I;BUY;9;9.60
TOTAL AMD Order count = 1
Msg #3 09:00:00.730000;AMD;2837176;I;SELL;5;36.30
TOTAL AMD Order count = 3
Msg #4 09:00:01.040000;AMD;2837177;I;SELL;2;36.60
TOTAL AMD Order count = 6
Msg #5 09:00:01.170000;AMD;2837174;A;SELL;72;36.00
TOTAL AMD Order count = 9
Msg #6 09:00:01.580000;AMD;2837178;I;SELL;620;36.00
TOTAL AMD Order count = 13
Msg #7 09:00:02.030000;AMD;2837179;I;BUY;59;35.20
TOTAL AMD Order count = 23
Msg #8 09:00:02.270000;OTHER;2837180;I;BUY;7;18.40
TOTAL AMD Order count = 33
Msg #9 09:00:03.040000;DVAM2;2837181;I;SELL;36;9.30
TOTAL AMD Order count = 43
Msg #10 09:00:03.240000;TEST0;2837182;I;SELL;76;23.20
TOTAL AMD Order count = 5
Msg #11 09:00:03.410000;AMD;2837177;C;SELL;2;36.60
TOTAL AMD Order count = 10
Msg #12 09:00:03.600000;AMD;2837174;C;SELL;72;36.00
TOTAL Order count = 16
Msg #13 09:00:04.170000;OTHER;2837183;I;BUY;8;18.20
TOTAL AMD Order count = 22
Msg #14 09:00:04.340000;AMD;2837179;C;BUY;59;35.20
TOTAL AMD Order count = 29
Msg #15 09:00:04.580000;AMD;2837184;I;BUY;3;35.10
TOTAL AMD Order count = 37
期望：從 Msg 1~15 得到的結果應該是 TOTAL AMD Order count = 10。上面錯誤的結果是 37。
即使結果是正確的，這種方法也是低效的，因為檢查每個票名非常耗時，例如 AMD、NVDA、TSLA……有成千上萬個票名。所以如果（），每次我們在地圖中發現計數器時增加計數器的 switch-case 方法是不好的，或者 unodered_map 對這個應用程式有好處，這個錯誤的結果僅僅是因為我的錯誤實作？我希望你能幫助我修改代碼，或者給我一個方向。
uj5u.com熱心網友回復：
當我們在第 2 列中遇到相應的名稱時，我自己使用 switch(cellID) 解決了它。我得到了預期的結果。無論如何，我仍然歡迎有人建議我一個更優化的解決方案，因為我的解決方案可能不是最好的。
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標籤：C 解析数据处理