從陣列中解碼1957年的字典

目標

1. 訪問陣列中的字典
2. 一些如何在不手動編碼每個股票名稱的情況下解碼所有 1957 年的字典。

下圖是來自

在此處回答的另一個問題的幫助下，我在下面包含了我正在嘗試更改以實作上述目標的代碼。

CallApi.swift - 此檔案呼叫 API 并將其建模為 PriceApiModel

import UIKit

class ViewController: UIViewController {
    
    let headers = [
        "X-RapidAPI-Key": "Sorry I cannot include this",
        "X-RapidAPI-Host": "binance43.p.rapidapi.com"
    ]

    let request = NSMutableURLRequest(url: NSURL(string: "https://binance43.p.rapidapi.com/ticker/price")! as URL,
                                            cachePolicy: .useProtocolCachePolicy,
                                        timeoutInterval: 10.0)
        

    func getData() {
        request.httpMethod = "GET"
        request.allHTTPHeaderFields = headers

        let session = URLSession.shared
        let dataTask = session.dataTask(with: request as URLRequest, completionHandler: { (data, response, error) -> Void in
            if (error != nil) {
                print("error")
            } else {
                let httpResponse = response as? HTTPURLResponse
                do {
                    //let dictionary = try JSONSerialization.jsonObject(with: data!, options: [])
                    let model = try JSONDecoder().decode(PriceApiModel.self, from: data!)
                    
                    //print(String(model.symbol)   "name") // please see output below
                    //print(dictionary)
                } catch {
                    print("NOT WORKING ")
                }
            }
        })
        dataTask.resume()
        
    }
}

PriceApiModel.swift - 我試圖找到一種方法讓這個檔案成為解碼資料的模型

struct PriceApiModel: Hashable, Codable {
    //changed the String type to Decimal
    var price: String

    // every property you are interested to decode needs a CodingKey.
    // You can omit values you are not interested in
    enum CodingKeys: CodingKey{
        case askPrice
    }
    
    // here you decode your data into the struct
    init(from decoder: Decoder) throws {
        // get the container
        let container = try decoder.container(keyedBy: CodingKeys.self)
        // decode the askPrice into a String and cast it into a Decimal
        let askPrice = String(try container.decode(String.self, forKey: .askPrice))
        // check if casting was succesfull else throw
        guard let askPrice = askPrice else{
            throw CustomError.decodingError
        }
        // assign it
        self.askPrice = askPrice
    }
}

uj5u.com熱心網友回復：

所以我只是嘗試了你想要在這里實作的目標。首先，您通過繼承 a 將服務類（獲取資料）宣告為 ViewController UIViewController。在我看來，只是在課堂上使用它有點奇怪，因為UIViewController沒有使用。其次，我建議您觀看或閱讀有關Codable例如Hackingforswift的內容。它至少幫助了我:)

但是，這是一個代碼，它向您展示了它的作業方式：

OptionalObject由于資料結構的原因，需要將所有內容保存在陣列中。

struct OptionalObject<Base: Decodable>: Decodable {
    public let value: Base?

    public init(from decoder: Decoder) throws {
        do {
            let container = try decoder.singleValueContainer()
            self.value = try container.decode(Base.self)
        } catch {
            self.value = nil
        }
    }
}

struct PriceApiModel: Codable {
    let price: String
    let symbol: String
}

class Service {
    
    let headers = [
        "X-RapidAPI-Key": "",
        "X-RapidAPI-Host": "binance43.p.rapidapi.com"
    ]

    let request = NSMutableURLRequest(
        url: URL(string: "https://binance43.p.rapidapi.com/ticker/price")!,
        cachePolicy: .useProtocolCachePolicy,
        timeoutInterval: 5.0
    )
    
    init() {
        self.getData()
    }

    func getData() {
        request.httpMethod = "GET"
        request.allHTTPHeaderFields = headers

        let session = URLSession.shared
        let dataTask = session.dataTask(with: request as URLRequest, completionHandler: { (data, response, error) -> Void in
            if let data = data {
                let model = try? JSONDecoder().decode([OptionalObject<PriceApiModel>].self, from: data)
                print(model?.compactMap { $0.value?.price })
                print(model?.compactMap { $0.value?.symbol })
            }
        })
        
        dataTask.resume()
    }
}

希望我能幫上忙。

標籤：json迅速代码解码

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