如何分隔串列中的元素以將它們作為值放入字典中

我想在字典中顯示具有所需字符的單詞。例如 ：

Write a sentence: Mister Jack, you are a good coder

{'a': ['are', 'jack,'], 'b': [], 'c': ['coder', 'jack,'], 'd': ['coder'], 'e': ['coder', 'mister',], 'f': [], 'g': [], 'h': [], 'i': ['mister'], 'j': ['jack,'], 'k': ['jack,'], 'l': [], 'm': ['mister', ], 'n': [], 'o': ['coder', 'you', 'good'], 'p': [], 'q': [], 'r': ['coder', 'mister'], 's': ['mister', ], 't': ['mister'], 'u': ['you'], 'v': [], 'w': [], 'x': [], 'y': ['you'], 'z': []}

這是我的代碼：

import string

alphabet = string.ascii_lowercase
sentence= (input("Write your sentence: " )).lower()
letter_notfound=(sorted(list((set(string.ascii_lowercase) - set("".join(sentence.split()))))))
print (letter_notfound)

letter_list=list(alphabet)
unique_letter = (sorted(list((set(letter_list)-set(letter_notfound)))))

dico={}

for key in (letter_list):
    for char in sentence:
        if char in unique_letter:
         dico[char] = [sentence]
    for char in letter_notfound:
        dico[char] = []
print(dict(sorted(dico.items())))

輸入： 杰克先生，你是個優秀的程式員

輸出：

{'a': ['mister jack, you are a good coder'], 'b': [], 'c': ['mister jack, you are a good coder'], 'd': ['mister jack, you are a good coder'], 'e': ['mister jack, you are a good coder'], 'f': [], 'g': ['mister jack, you are 
a good coder'], 'h': [], 'i': ['mister jack, you are a good coder'], 'j': ['mister jack, you are a good coder'], 'k': ['mister jack, you are a good coder'], 'l': [], 'm': ['mister jack, you are a good coder'], 'n': [], 'o': ['mister jack, you are a good coder'], 'p': [], 'q': [], 'r': ['mister jack, you are a good coder'], 's': ['mister jack, you are a good coder'], 't': ['mister jack, you are a good coder'], 'u': ['mister jack, you are a good coder'], 'v': [], 'w': [], 'x': [], 'y': ['mister jack, you are a good coder'], 'z': []}

期望的輸出：

{'a': ['are', 'jack,'], 'b': [], 'c': ['coder', 'jack,'], 'd': ['coder'], 'e': ['coder', 'mister',], 'f': [], 'g': [], 'h': [], 'i': ['mister'], 'j': ['jack,'], 'k': ['jack,'], 'l': [], 'm': ['mister', ], 'n': [], 'o': ['coder', 'you', 'good'], 'p': [], 'q': [], 'r': ['coder', 'mister'], 's': ['mister', ], 't': ['mister'], 'u': ['you'], 'v': [], 'w': [], 'x': [], 'y': ['you'], 'z': []}

uj5u.com熱心網友回復：

使用串列/字典理解的更多“Pythonic” ：

words = sentence.split(' ') # Assuming already lowercase
alphabet_dict = {x: [w for w in words if x in w] for x in ascii_lowercase}

理解不僅更簡潔，而且更具宣告性而不是命令性，因此在大多數情況下更容易理解，因為它更容易說明是什么而不是如何。

我推薦閱讀何時在 Python 中使用串列理解

uj5u.com熱心網友回復：

我建議的第一件事是遍歷單詞，因為只有它們對你很重要。你可以得到他們split

words = sentence.split()

第二件事是您無處可將新詞附加到現有密鑰。你應該從準備字典開始。

dico = {letter: [] for letter in alphabet}

現在應該很容易檢查字母是否在單詞中。

for letter im letter_list:
    for word in words:
        if letter in word:
            dico[letter].append(word)

uj5u.com熱心網友回復：

這將創建一個帶有字母的字典，然后將輸入轉換為由單詞分隔的串列。然后我們遍歷這些字母并檢查它是否在字母字典中，如果是的話，我們會附加這個詞。

import string

alphabet = string.ascii_lowercase
alphabet_dict = {alphabet[i]: [] for i in range(len(alphabet))}
input_list = input("Enter a string: ").split(" ")
for word in input_list:
    for letter in word:
        if letter in alphabet_dict:
            alphabet_dict[letter].append(word)
alphabet_dict = dict(sorted(alphabet_dict.items(), key=lambda item: item[0]))
print(alphabet_dict)

標籤：Python列表字典for循环放

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