如何列印Congrats而不出現python中的錯誤-有解無憂

程式如下，要求選擇一個產品，然后詢問選擇的金額，然后用戶輸入金額，但如果金額與宣告的值（mo）不同，程式會列印“錯誤的硬幣”，但是當用戶輸入正確的硬幣和金額時，它應該只列印代碼的“找零”部分。在我的程式中，它列印“找零”然后錯誤的硬幣價值

prod = ["Coffe", "Coffee with milk", "Chocolate", "Chocolate with milk"]
cost = [1.5, 1.8, 2.1, 2.4]
mo = [0.1, 0.2, 0.5, 1, 2, 5, 10]

item_number = len(prod)

print("\nPick an item:")

for number in range(0, item_number, 1):
    print(number   1,
    prod [number],
    '{0:.2f}€'.format(cost[number]))

print ("0 Exit")

choice = int(input("Please pick an item from (1-4) or hit 0 to exit: ")) -1

if choice < item_number and choice >= 0:
    print("You should input", "{0:.2f}€".format(cost[choice]), 'in total')
else:
        print("Exiting the program")
        exit(0)

money = float(input("How much do you enter?; "))

while money < cost[choice]:
    money  = float(input("You should insert " str("{:.2f}".format(cost[choice] - money))))

if money != mo:
    print("Invalid amount.\nPlease enter a valid coin: 0.1 / 0.2 / 0.5 / 1 / 2 / 5 / 10")
else:
    print("Try again")
change = money - cost[choice]

print("Change {0:.2f}€".format(change))

uj5u.com熱心網友回復：

邏輯可能不一樣

不斷要錢（while True允許寫input一次）
驗證選擇是否在串列中不相等（afloat不能等于 a list）
增加您的總金額
如果你有足夠的停止

money = 0
while True:
    new_money = float(input(f"You should insert {cost[choice] - money:.2f}: "))
    if new_money not in mo:
        print("Invalid amount.\nPlease enter a valid coin: "   "/".join(map(str, mo)))
        continue
    money  = new_money
    if money >= cost[choice]:
        break
change = money - cost[choice]
print(f"Change {change:.2f}€")

其他代碼，有一些改進

print("\nPick an item:")
for number in range(item_number, ):
    print(f'{number   1} {prod[number]} {cost[number]:.2f}€')
print("0 Exit")

choice = int(input("Please pick an item from (1-4) or hit 0 to exit: ")) - 1
if 0 < choice <= item_number:
    print(f"You should input {cost[choice]:.2f}€", 'in total')
else:
    print("Exiting the program")
    exit(0)

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