我正在將 16 位數字從 STM32（來自 ADC）通過 SPI 傳輸到 raspberry pi 4。在 pi 方面，我有一個回圈運行的腳本，等待 GPIO 引腳變高以充當“檢測”我的系統然后啟用樹莓派啟動 SPI 傳輸。不幸的是，樹莓派硬體僅支持 8 位 SPI，因此我回傳的數字分為 2 x 8 位。我正在傳輸的資料：
uint16_t spi_test_16[64] = {1023, 19, 38, 47, 51, 52, 53, 59, 76, 91, 99, 119, 172, 174,
179, 205, 215, 218, 225, 235, 242, 264, 284, 308, 316, 334, 404, 431, 434,
442, 442, 457, 468, 479, 490, 496, 508, 509, 512, 523, 524, 524, 525, 589, 598,
642, 674, 711, 716, 749, 761, 767, 771, 788, 790, 818, 854, 928, 935, 947, 964,
976, 987, 996}
和我收到的資料：
(255, 3, 19, 0, 38, 0, 47, 0, 51, 0, 52, 0, 53, 0, 59, 0, 76, 0, 91, 0, 99, 0, 119, 0, 172, 0 174, 0, 179, 0, 205, 0, 215, 0, 218, 0, 225, 0, 235, 0, 242, 0, 8, 1, 28, 1, 52, 1, 60, 1, 78, 1, 148, 1, 175, 1, 178, 1, 186, 1, 186, 1, 201, 1, 212, 1, 223, 1, 234, 1, 240, 1, 252, 1, 253, 1, 0, 2, 11, 2, 12, 2, 12, 2, 13, 2, 77, 2, 86, 2, 130, 2, 162, 2, 199, 2, 204, 2, 237, 2, 249, 2, 255, 2, 3, 3, 20, 3, 22, 3, 50, 3, 86, 3, 160, 3, 167, 3, 179, 3, 196, 3, 208, 3, 219, 3, 228, 3)
正如您所看到的，它獲得了正確的數字，但它們的格式不正確，因為它是 2 x 8 位格式。我需要幫助以使用 Python 將值恢復為原始格式。我的代碼：
#a simple test for spi
import spidev
import time
import RPi.GPIO as GPIO
import numpy
GPIO.setmode(GPIO.BOARD)
GPIO.setup(26, GPIO.IN)
GPIO.setup(40, GPIO.OUT)
#using spi0
bus = 0
#device is chip select.
device = 0
#enable
spi = spidev.SpiDev()
#open a connection to a specific bus and device (CS pin)
spi.open(bus, device)
#set spi speed and mode
spi.max_speed_hz = 100000
spi.mode = 0
spi.bits_per_word = 8
#msg = ["Hello! "]
msg = [72, 101, 108, 108, 111, 33, 32]
buffer_size = 128
spi_buffer = [0]*buffer_size
msgRx = 0;
flag = 0
print ("python spi test program with STM32")
#GPIO.output(7,0)
GPIO.output(40,1)
time.sleep (1)
while True :
if GPIO.input(26) == 1:
#print ("Message receiving")
time.sleep(0.1)
if GPIO.input(26) == 1:
GPIO.output(40,0)
#msgRx = spi.readbytes(160)
msgRx = spi.xfer3(spi_buffer)
GPIO.output(40,1)
print (msgRx)
##listofzeroes = [0]*50000
print("msgRx reset")
msgRx = numpy.asarray(msgRx, dtype=numpy.uint16)
for index, value in enumerate(msgRx):
msgRx[index] >> 8
print (msgRx)
time.sleep(1)
#flag = 1
#if flag == 1:
#print("Message Complete")
#flag = 0
我嘗試了幾件事，但目前在主 While 回圈中，我將接收到的串列轉換為 16 位無符號整數陣列，然后向左移位。但是，如何將陣列的第二個單元格添加到第一個等？
TDLR；如何將 2 x 8 位整數串列轉換為 1 x 16 位整數串列？
uj5u.com熱心網友回復：
使用 numpy：
In [9]: data = (255, 3, 19, 0, 38, 0, 47, 0, 51, 0, 52, 0, 53, 0, 59, 0, 76, 0, 91, 0, 99, 0, 119, 0, 172, 0, 174, 0, 179, 0, 205, 0, 215, 0, 218, 0, 225, 0, 235, 0, 242, 0, 8, 1, 28, 1, 52, 1, 60, 1, 78, 1, 148, 1, 175, 1, 178, 1,
...: 186, 1, 186, 1, 201, 1, 212, 1, 223, 1, 234, 1, 240, 1, 252, 1, 253, 1, 0, 2, 11, 2, 12, 2, 12, 2, 13, 2, 77, 2, 86, 2, 130, 2, 162, 2, 199, 2, 204, 2, 237, 2, 249, 2, 255, 2, 3, 3, 20, 3, 22, 3, 50, 3, 86, 3, 160, 3, 167, 3,
...: 179, 3, 196, 3, 208, 3, 219, 3, 228, 3)
...:
In [10]: arr = np.array(data, np.uint8)
看起來在你的元組中，你有unsigned 8-bit integers。因此，只需將其創建為無符號 16 位整數即可：
In [11]: arr = arr.view(np.uint16)
In [12]: arr
Out[12]:
array([1023, 19, 38, 47, 51, 52, 53, 59, 76, 91, 99,
119, 172, 174, 179, 205, 215, 218, 225, 235, 242, 264,
284, 308, 316, 334, 404, 431, 434, 442, 442, 457, 468,
479, 490, 496, 508, 509, 512, 523, 524, 524, 525, 589,
598, 642, 674, 711, 716, 749, 761, 767, 771, 788, 790,
818, 854, 928, 935, 947, 964, 976, 987, 996], dtype=uint16)
如評論中所述，為了使上述可移植，您可以使用以下符號指定位元組序：
arr = arr.view('<H').
< 表示“little-endian”，H 是無符號 16 位整數的字符代碼。有關指定 dtype 的更多資訊，請參閱檔案。
請注意，我不知道您正在使用的庫，但您有一條注釋掉的行：
msgRx = spi.readbytes(160)
可能，您只想使用它，但讀取 128 個位元組（對于 64 個無符號 16 位整數）然后使用np.frombuffer：
msgRx = spi.readbytes(128)
msgRx = numpy.frombuffer(msgRx, dtype=numpy.uint16)
uj5u.com熱心網友回復：
這是有效的：
def to_bin(int_num):
return '{0:08b}'.format(int_num)
def to_int(bina):
return int(bina, 2)
def transform(int_num_1, int_num_2):
print(f"{int_num_1 = }")
print(f"{int_num_2 = }")
bina_1 = to_bin(int_num_1)
bina_2 = to_bin(int_num_2)
print(f"{bina_1 = }")
print(f"{bina_2 = }")
trame = bina_2 bina_1
print(f"{trame = }")
result = to_int(trame)
print(f"{result = }")
return result
input_list = [255, 3, 19, 0, 38, 0, 47, 0, 51, 0, 52, 0, 53, 0, 59, 0, 76, 0, 91, 0, 99, 0, 119, 0, 172, 0, 174, 0, 179, 0, 205, 0, 215, 0, 218, 0, 225, 0, 235, 0, 242, 0, 8, 1, 28, 1, 52, 1, 60, 1, 78, 1, 148, 1, 175, 1, 178, 1, 186, 1, 186, 1, 201, 1, 212, 1, 223, 1, 234, 1, 240, 1, 252, 1, 253, 1, 0, 2, 11, 2, 12, 2, 12, 2, 13, 2, 77, 2, 86, 2, 130, 2, 162, 2, 199, 2, 204, 2, 237, 2, 249, 2, 255, 2, 3, 3, 20, 3, 22, 3, 50, 3, 86, 3, 160, 3, 167, 3, 179, 3, 196, 3, 208, 3, 219, 3, 228, 3]
for i in range(len(input_list)//2):
transform(input_list[i*2], input_list[i*2 1])
訣竅是轉換為二進制檔案，將它們連接起來并重新轉換為整數。
前 3 個結果：
int_num_1 = 255
int_num_2 = 3
bina_1 = '11111111'
bina_2 = '00000011'
trame = '0000001111111111'
result = 1023
int_num_1 = 19
int_num_2 = 0
bina_1 = '00010011'
bina_2 = '00000000'
trame = '0000000000010011'
result = 19
int_num_1 = 38
int_num_2 = 0
bina_1 = '00100110'
bina_2 = '00000000'
trame = '0000000000100110'
result = 38
編輯：使用@juanpa.arrivillaga 的答案（快得多）。拿這個答案來了解它是如何作業的！
轉載請註明出處，本文鏈接：https://www.uj5u.com/yidong/383415.html