A. Shifting Stacks
這題我能記很久,直接給我打自閉了,從開賽一直到了最后,我就一個菜雞
題意非常簡單,給你n個數,讓你把他們構造成遞增的,然后只能從后往前,你直接想就行了,直接構造0 1 2 3 4 5 6 7 8 9…n如果可以的話,就是yes,不可以的話就是no
然后上我第一遍的代碼
#include <bits/stdc++.h>
#define int long long
#define BUFF ios::sync_with_stdio(false), cin.tie(0), cout.tie(0)
using namespace std;
const int N = 2e5 + 10;
const int INF = 0x3f3f3f3f;
inline int read()
{
int x = 0, f = 1;
char ch = getchar();
while (ch < '0' || ch > '9')
{
if (ch == '-')
f = -1;
ch = getchar();
}
while (ch >= '0' && ch <= '9')
{
x = x * 10 + ch - '0';
ch = getchar();
}
return x * f;
}
int a[N];
signed main()
{
/*
freopen("in.txt","r",stdin);
freopen("out.txt","w",stdout);
*/
int T;
T = read();
while (T--)
{
int n;
n = read();
bool flag = true;
int cnt = 0;
for (int i = 1; i <= n; i++)
{
a[i] = read();
}
for (int i = 1; i < n; i++)
{
int ans = a[i] - cnt;
a[i] = cnt;
cnt++;
if (ans < 0)
{
flag = false;
break;
}
a[i + 1] += ans;
if (a[i] >= a[i + 1])
{
flag = false;
break;
}
}
if (a[n] <= a[n - 1])
{
flag = false;
}
if (flag)
cout << "YES" << endl;
else
cout << "NO" << endl;
}
return 0;
}
這個讓人直接wa掉,因為我少了一個特判,如果n==1的時候,我要直接yes,而不是判斷a[1]和a[0]的關系
然后下面是ac的代碼
#include <bits/stdc++.h>
#define int long long
#define BUFF ios::sync_with_stdio(false), cin.tie(0), cout.tie(0)
using namespace std;
const int N = 2e5 + 10;
const int INF = 0x3f3f3f3f;
inline int read()
{
int x = 0, f = 1;
char ch = getchar();
while (ch < '0' || ch > '9')
{
if (ch == '-')
f = -1;
ch = getchar();
}
while (ch >= '0' && ch <= '9')
{
x = x * 10 + ch - '0';
ch = getchar();
}
return x * f;
}
int a[N];
signed main()
{
/*
freopen("in.txt","r",stdin);
freopen("out.txt","w",stdout);
*/
int T;
T = read();
while (T--)
{
int n;
n = read();
bool flag = true;
int cnt = 0;
for (int i = 1; i <= n; i++)
{
a[i] = read();
}
if (n == 1)
{
cout << "YES" << endl;
continue;
}
for (int i = 1; i < n; i++)
{
int ans = a[i] - cnt;
a[i] = cnt;
cnt++;
if (ans < 0)
{
flag = false;
break;
}
a[i + 1] += ans;
if (a[i] >= a[i + 1])
{
flag = false;
break;
}
}
if (a[n] <= a[n - 1])
{
flag = false;
}
if (flag)
cout << "YES" << endl;
else
cout << "NO" << endl;
}
return 0;
}
就加了一個特判就好了,我直接上圖,我wa的人傻了的圖

剩下的題補完再更新
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