為每個表行創建n分鐘間隔

我正在嘗試根據表格獲取時間間隔。

我的源表是這樣的：

期望的輸出：

TIME_BEG和TIME_END是VARCHAR列，但我也有它們，DAY TO SECOND INTERVAL此處未顯示（分別為 TIME_BEG_INT 和 TIME_END_INT）。

基本上，我需要TRUNC (EXTRACT (DAY FROM 24 * 60 * (TIME_END_INT - TIME_BEG_INT)) / DURATION)在一個 SQL 中復制每一行時間并將 this*DURATION 添加到我的日期中。

任何幫助表示贊賞。

uj5u.com熱心網友回復：

如果您使用間隔：

CREATE TABLE table_name (ID, OTHER_DATA, TIME_BEG, TIME_END, DURATION) AS
SELECT 1, 'abcd', INTERVAL '10:00' HOUR TO MINUTE, INTERVAL '11:00' HOUR TO MINUTE, INTERVAL '15' MINUTE FROM DUAL UNION ALL
SELECT 2, 'xyzt', INTERVAL '16:00' HOUR TO MINUTE, INTERVAL '17:00' HOUR TO MINUTE, INTERVAL '30' MINUTE FROM DUAL;

然后你可以使用：

WITH range (ID, OTHER_DATA, TIME_BEG, TIME_INT_END, TIME_END, DURATION) AS (
  SELECT ID,
         OTHER_DATA,
         TIME_BEG,
         LEAST(time_beg   duration, time_end),
         TIME_END,
         DURATION
  FROM   table_name
UNION ALL
  SELECT ID,
         OTHER_DATA,
         TIME_INT_END,
         LEAST(time_int_end   duration, time_end),
         TIME_END,
         DURATION
  FROM   range
  WHERE  time_int_end < time_end
)
SEARCH DEPTH FIRST BY id SET id_order
SELECT ID,
       OTHER_DATA,
       TIME_BEG AS itvl_beg,
       TIME_INT_END AS itvl_end
FROM   range;

哪些輸出：

ID	OTHER_DATA	ITVL_BEG	ITVL_END
1	A B C D	000000000 10:00:00.000000000	000000000 10:15:00.000000000
1	A B C D	000000000 10:15:00.000000000	000000000 10:30:00.000000000
1	A B C D	000000000 10:30:00.000000000	000000000 10:45:00.000000000
1	A B C D	000000000 10:45:00.000000000	000000000 11:00:00.000000000
2	xyzt	000000000 16:00:00.000000000	000000000 16:30:00.000000000
2	xyzt	000000000 16:30:00.000000000	000000000 17:00:00.000000000

如果您將值作為字串，則可以先將它們轉換為間隔：

CREATE TABLE table_name (ID, OTHER_DATA, TIME_BEG, TIME_END, DURATION) AS
SELECT 1, 'abcd', '10:00', '11:00', 15 FROM DUAL UNION ALL
SELECT 2, 'xyzt', '16:00', '17:00', 30 FROM DUAL;

WITH data(ID, OTHER_DATA, TIME_BEG, TIME_END, DURATION) AS (
  SELECT ID,
         OTHER_DATA,
         TO_DSINTERVAL('0 '||TIME_BEG||':00'),
         TO_DSINTERVAL('0 '||TIME_END||':00'),
         NUMTODSINTERVAL(DURATION, 'MINUTE')
  FROM   table_name
),
range (ID, OTHER_DATA, TIME_BEG, TIME_INT_END, TIME_END, DURATION) AS (
  SELECT ID,
         OTHER_DATA,
         TIME_BEG,
         LEAST(time_beg   duration, time_end),
         TIME_END,
         DURATION
  FROM   data
UNION ALL
  SELECT ID,
         OTHER_DATA,
         TIME_INT_END,
         LEAST(time_int_end   duration, time_end),
         TIME_END,
         DURATION
  FROM   range
  WHERE  time_int_end < time_end
)
SEARCH DEPTH FIRST BY id SET id_order
SELECT ID,
       OTHER_DATA,
       TIME_BEG AS itvl_beg,
       TIME_INT_END AS itvl_end
FROM   range;

db<>在這里擺弄

uj5u.com熱心網友回復：

這是基于間隔前計算的經典解決方案 DATE

with time_int(ID, OTHER_DATA, ITVL_BEG, ITVL_END, DURATION, TIME_END) as (
select 
 ID, OTHER_DATA, TIME_BEG, 
 to_char(to_date(time_beg,'HH24:mi') duration/(24*60),'HH24:mi'), 
 DURATION, TIME_END 
from tab
union all
select 
 ID, OTHER_DATA, ITVL_END, 
 to_char(to_date(ITVL_END,'HH24:mi') duration/(24*60),'HH24:mi'), 
 DURATION, TIME_END 
from time_int
where ITVL_END <= TIME_END
)
select 
   ID, OTHER_DATA, ITVL_BEG, ITVL_END
from time_int
order by 1,3;

        ID OTHE ITVL_ ITVL_
---------- ---- ----- -----
         1 abcd 10:00 10:15
         1 abcd 10:15 10:30
         1 abcd 10:30 10:45
         1 abcd 10:45 11:00
         1 abcd 11:00 11:15
         2 xyzt 16:00 16:30
         2 xyzt 16:30 17:00
         2 xyzt 17:00 17:30

甲遞回CTE用于與步驟基于以下計算獲得下一個間隔邊界（假設你的時間被存盤為VARCHAR2）

to_char(to_date(time_beg,'HH24:mi') duration/(24*60),'HH24:mi')

請注意，您可以轉換10:00為日期，并且 Oracle 提供了您不需要的默認缺失日、月和年，因為在增加之后duration您會轉換回HH24:MI字串。

標籤：sql 甲骨文 日期时间转换

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