如何在c 中洗掉斐波那契數列中的最后一個數字0？

我正在嘗試洗掉斐波那契數列中的最后一個 0

因為我正在洗掉 return 0; 最后一個值顯示垃圾值

類似于 735150

我應該編輯什么以獲得所需的輸出

0 1 2 3 5 8 13 21 34 55 89 144 233 377 610 987 1597 2584 4181

因為我得到了輸出

0 1 2 3 5 8 13 21 34 55 89 144 233 377 610 987 1597 2584 4181 0

#include <iostream>
using namespace std;

class fibo
{
private:

unsigned long int n1,n2,final;

public:
fibo()
{
    n1 = 0;
    n2 = 1;
    final = n1   n2;
}

fibo(int x1,int x2) //Parameterised Constructor
{
    n1 = x1;
    n2 = x2;
    for (int x = 0;x<=8; x  )
    {
        final = n1   n2;
        cout << final << " ";
        n1 = n2;
        n2 = final;
    }
    
}

int calc()
{
    for (int x = 0;x<=8; x  )
    {
        final = n1   n2;
        cout << final << " ";
        n1 = n2;
        n2 = final;
    }
    return 0;
}

fibo(fibo &i); // Copy Constructor
};

fibo::fibo(fibo &i)
{
n1= i.n1;
n2 = i.n2;
final = i.final;
}

int main()
{
cout << "0 " ;
fibo f1(0,1);
fibo f2 = f1;

cout << f2.calc() << endl;

 return 0;
}

uj5u.com熱心網友回復：

我非常清楚這不是代碼審查，而是 OP 要求提供一個更簡單的版本。

這不符合奇數復制建構式的要求，而是表明列印斐波那契數可以在幾行 (8) 行代碼中處理。

#include <iostream>
#include <vector>
#include <algorithm>

// This is a poor time to use a classes and objects,
// This is simply a straightforward algorithm.
// calculation is not an object
// As Nathan says, it is a bizarre design

// Generate numbers
std::vector<int> fibonacci_numbers(int N){
    auto n0 = 0; // not used in output
    auto n1 = 1; // first value in output
    auto next_fib = [&n0,&n1](){
        auto value = n1;
        auto next = n0   n1;
        n0 = n1;
        n1 = next;
        return value;
    };
    auto result = std::vector<int>(N);
    std::generate(result.begin(), result.end(), next_fib);
    return result;
}

// Print
void print_fibo(int N){
    int n0 = 0; // not for printing
    int n1 = 1;
    while(N--){
        auto next_fib = n0   n1;
        std::cout << n1 << ", ";
        n0 = n1;
        n1 = next_fib;
    }
}

int main() {
    // seems like you want 19 numbers
    // generating
    auto fibs = fibonacci_numbers(9);
    for(auto e:fibs){
        std::cout << e << ", ";
    }
    // just printing
    std::cout << '\n';
    print_fibo(19);
    std::cout << '\n';
    return 0;
}

uj5u.com熱心網友回復：

我做了一些更改，如下面的代碼所示。首先，您不需要創建物件 f1 的副本。直接呼叫即可f1.calc()。Secondcalc的回傳型別更改為 void。第三，使用建構式初始化串列。您可以在此處查看作業程式。

#include <iostream>
using namespace std;

class fibo
{
private:

unsigned long int n1,n2,final;

public:
//use constructor initializer list
fibo(): n1(0), n2(1), final(n1 n2)
{
    //n1 = 0;
    //n2 = 1;
    //final = n1   n2;
}

fibo(int x1,int x2) //Parameterised Constructor
{
    n1 = x1;
    n2 = x2;
    for (int x = 0;x<=8; x  )
    {
        final = n1   n2;
        cout << final << " ";
        n1 = n2;
        n2 = final;
    }
    
}

void calc()
{
    for (int x = 0;x<=8; x  )
    {
        final = n1   n2;
        cout << final << " ";
        n1 = n2;
        n2 = final;
    }
    //no need to return
    //return 0;
}

fibo(fibo &i); // Copy Constructor
};

fibo::fibo(fibo &i)
{
n1= i.n1;
n2 = i.n2;
final = i.final;
}

int main()
{
cout << "0 1 " ;
fibo f1(0,1);

//no need to create new object
//fibo f2 = f1;

//call f1.calc() instead of f2.calc()
f1.calc();

 return 0;
}

上面程式的輸出是：

0 1 1 2 3 5 8 13 21 34 55 89 144 233 377 610 987 1597 2584 4181 

請注意，還有其他方法可以實作這一點。您可以在此處查看這些內容。

此外，在給定的示例代碼輸出，開始3個數字應該是0 1 1而不是0 1 2。您可以cout << "0 ";到cout << "0 1 ";得到正確的輸出0 1 1，因為我在我的編輯一樣。

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