力扣468. 驗證IP地址
題目描述:

示例1??:
輸入:IP = "172.16.254.1"
輸出:"IPv4"
解釋:有效的 IPv4 地址,回傳 "IPv4"
示例2??:
輸入:IP = "2001:0db8:85a3:0:0:8A2E:0370:7334"
輸出:"IPv6"
解釋:有效的 IPv6 地址,回傳 "IPv6"
示例3??:
輸入:IP = "256.256.256.256"
輸出:"Neither"
解釋:既不是 IPv4 地址,又不是 IPv6 地址
示例4??:
輸入:IP = "2001:0db8:85a3:0:0:8A2E:0370:7334:"
輸出:"Neither"
示例5??:
輸入:IP = "1e1.4.5.6"
輸出:"Neither"
看到有明顯的字符規則,想到正則運算式,否則一行一行碼過去
代碼一,正則運算式:
class Solution {
public:
string validIPAddress(string IP) {
regex i4("(([0-9]|[1-9][0-9]|1[0-9][0-9]|2[0-4][0-9]|25[0-5])\\.){3}([0-9]|[1-9][0-9]|1[0-9][0-9]|2[0-4][0-9]|25[0-5])");
regex i6("([0-9a-fA-F]{1,4}\\:){7}[0-9a-fA-F]{1,4}");
if (regex_match(IP, i4)) return "IPv4";
else if (regex_match(IP, i6)) return "IPv6";
else return "Neither";
}
};
正則運算式學習入口1
正則運算式學習入口2

代碼二:遍歷,判斷,一個條件一個條件限制,
class Solution {
public:
string validIPAddress(string IP) {
if(is4(IP))return "IPv4";
else if(is6(IP))return "IPv6";
return "Neither";
}
bool is4(string IP){
vector<string>ip;
split(IP,ip,'.');
if(ip.size()!=4)return false;
for(string s:ip){
if(s.size()==0||(s.size()>1&&s[0]=='0')||s.size()>3)return false;
for(char c:s){
if(!isdigit(c))return false;
}
int digit=stoi(s);
if(digit<0||digit>255)return false;
}
return true;
}
bool is6(string IP){
vector<string>ip;
split(IP,ip,':');
if(ip.size()!=8)return false;
for(string s:ip){
if(s.size()==0||s.size()>4)return false;
for(char c:s){
if(c<'0'||c>'9'&&c<'A'||c>'F'&&c<'a'||c>'f')return false;
}
}
return true;
}
void split(string s,vector<string>&ip,char c){
stringstream ss(s);
string tmp;
while(getline(ss,tmp,c))ip.push_back(tmp);
if(s.size()>0&&s.back()==c)ip.push_back({});
}
};
//從力扣題解摘下來的,我要先休息一下,
作者:zhouzihong
鏈接:https://leetcode-cn.com/problems/validate-ip-address/solution/mian-shi-guan-xiang-kan-dao-shi-yao-qie-d23jw/
來源:力扣(LeetCode)
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