所以我寫了這個接受檔案的代碼，并以filename: str' ' 的形式回傳字串中每個字母存在的次數..這是我的代碼
def letterhelper(filename):
r = list(filename)
c_r = set(r)
c_r.remove(' ')
c_r.remove(',')
c_r.remove('.')
c_r.remove('\n')
f = []
for x in c_r:
f.append([-r.count(x), x])
return f
def charHistogram(data: str):
r = open(filename)
q = r.read()
g = letterhelper(str.lower(q))
for t in sorted(g):
print(t[1], (-t[0]) * ' ')
和資料是一個單獨的檔案，它將被函式打開 letterhelper()
資料可能包含的示例輸入是...
“我的兄弟姐妹給我壓力”
所以，問題是，當data是
Lorem ipsum dolor sit amet, consectetur adipiscing
elit. Praesent ac sem lorem. Integer elementum
ultrices purus, sit amet malesuada tortor
pharetra ac. Vestibulum sapien nibh, dapibus
nec bibendum sit amet, sodales id justo.
函式正確回傳
e
t
s
i
a
m
r
u
l
n
o
c
d
p
b
g
h
j
v
None
但如果data=Someday Imma be greater than the rest
輸出是
c_r.remove(',')
KeyError: ','
我應該進行哪些更改，以便我的代碼正確回傳直方圖，例如data“Lorem ipsum .....”何時為提供的所有字串輸入？
uj5u.com熱心網友回復：
以下內容將解決該問題，并使您將來可以更輕松地添加更多字符以進行洗掉。
def letterhelper(filename):
r = list(filename)
c_r = set(r)
chars_to_remove = (' ', ',', '.', '\n')
for char in chars_to_remove:
if char in c_r:
c_r.remove(char)
f = []
for x in c_r:
f.append([-r.count(x), x])
return f
.
.
.
.
.
.
如果您需要有關代碼的建議。
def letterhelper(filename): # I GUESS you wanted the parameter here to be 'data' and not 'filename'
r = list(filename) # You don't need to convert str to list for using 'count' method
c_r = set(r)
chars_to_remove = (' ', ',', '.', '\n')
for char in chars_to_remove:
if char in c_r:
c_r.remove(char)
f = [] # You can use list comprehentions
for x in c_r:
f.append([-r.count(x), x]) # you don't need to negate the count here, you can reverse the sorted list in the function 'charHistogram'
return f
def charHistogram(data: str): # I GUESS you wanted the parameter here to be 'filename' and not 'data'
r = open(filename) # It is always a good practice to close the file as soon as you are done with it
q = r.read()
g = letterhelper(str.lower(q))
for t in sorted(g): # sorted(g, reverse=True)
print(t[1], (-t[0]) * ' ') # t[0] * ' '
以下是我能想到的。
def letterhelper(data: str):
chars_to_remove = (" ", ",", ".", "\n")
# f = []
# for x in set(data):
# if x not in chars_to_remove:
# f.append((data.count(x), x))
# The list comprehention in the next line does exactly the same thing as the for loop above
f = [(data.count(x), x) for x in set(data) if x not in chars_to_remove]
return f
def charHistogram(filename: str):
# r = open(filename)
# q = r.read()
# r.close()
# The with statement in the next line does exactly the same thing as the 3 lines above
with open(filename) as r:
q = r.read()
g = letterhelper(str.lower(q)) # q.lower() will also work
for t in sorted(g, reverse=True): # this will sort the list in descending order
print(t[1], t[0] * " ")
uj5u.com熱心網友回復：
簡單：
if ',' in c_r:
c_r.remove(',')
那應該是一個有效的操作。
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