比較兩個物件并創建新物件

我有兩個物件如下：

var1 = {
    "ELEMENT1": [1110,1111],
    "ELEMENT2": ["909"],
    "ELEMENT3": ["910"]
}

var2 =  {
    "ELEMENT3": [
    {
        "ID":910,
        "NAME":"ELEMENT3",
        "DETAILS":"CURRENT"
    },
    {
        "ID":912,
        "NAME":"ELEMENT3",
        "DETAILS":"FUTURE"
    }
    ],
    "ELEMENT2":[
    {
        "ID":909,
        "NAME": "ELEMENT2",
        "DETAILS":"OUTAGE"
    },
    {
        "ID": 910,
        "NAME": "ELEMENT2",
        "DETAILS":"OUTAGE"
    }
    ],
    "ELEMENT1":[
    {
        "ID": 1110,
        "NAME": "WORK_PACKAGE",
        "DETAILS": "INLINE"
    },
    {
        "ID": 1111,
        "NAME": "WORK_PACKAGE",
        "DETAILS": "INLINE"
    },
    {
        "ID": 1112,
        "NAME": "WORK_PACKAGE",
        "DETAILS": "INLINE"
    },
    {
        "ID": 1113,
        "NAME": "WORK_PACKAGE",
        "DETAILS": "INLINE"
    }]
}

我試圖在比較var1和之后創建第三個物件var2。第三個物件應該只包含那些ID存在于var1.

第三個物件應如下所示：

{
    "ELEMENT3": [
    {
        "ID":910,
        "NAME":"ELEMENT3",
        "DETAILS":"CURRENT"
    }
    ],
    "ELEMENT2":[
    {
        "ID":909,
        "NAME": "ELEMENT2",
        "DETAILS":"OUTAGE"
    }
    ],
    "ELEMENT1":[
    {
        "ID": 1110,
        "NAME": "WORK_PACKAGE",
        "DETAILS": "INLINE"
    },
    {
        "ID": 1111,
        "NAME": "WORK_PACKAGE",
        "DETAILS": "INLINE"
    }
    ]
}

uj5u.com熱心網友回復：

這應該這樣做：

var var1 = {
    "ELEMENT1": ["1110","1111"],
    "ELEMENT2": ["909"],
    "ELEMENT3": ["910"]
}

var var2 =  {
    "ELEMENT3": [
    {
        "ID":910,
        "NAME":"ELEMENT3",
        "DETAILS":"CURRENT"
    },
    {
        "ID":912,
        "NAME":"ELEMENT3",
        "DETAILS":"FUTURE"
    }
    ],
    "ELEMENT2":[
    {
        "ID":909,
        "NAME": "ELEMENT2",
        "DETAILS":"OUTAGE"
    },
    {
        "ID": 910,
        "NAME": "ELEMENT2",
        "DETAILS":"OUTAGE"
    }
    ],
    "ELEMENT1":[
    {
        "ID": 1110,
        "NAME": "WORK_PACKAGE",
        "DETAILS": "INLINE"
    },
    {
        "ID": 1111,
        "NAME": "WORK_PACKAGE",
        "DETAILS": "INLINE"
    },
    {
        "ID": 1112,
        "NAME": "WORK_PACKAGE",
        "DETAILS": "INLINE"
    },
    {
        "ID": 1113,
        "NAME": "WORK_PACKAGE",
        "DETAILS": "INLINE"
    }]
}

var obj = {};
Object.keys(var2).forEach((item) => {
  var2[item].forEach((subItem) => {
    if(var1[item].indexOf(`${subItem.ID}`) > -1) {
      obj[item] = [...(obj[item] ?? []), subItem]
    }
  })
});

console.log(obj);

uj5u.com熱心網友回復：

您可以回圈var2并過濾包含過濾后的道具并將其分配給新物件的IDs ：var1

let var1 = {
  ELEMENT1: [1110, 1111],
  ELEMENT2: [909],
  ELEMENT3: [910],
}

let var2 = {
  ELEMENT3: [
    { ID: 910, NAME: 'ELEMENT3', DETAILS: 'CURRENT' },
    { ID: 912, NAME: 'ELEMENT3', DETAILS: 'FUTURE' },
  ],
  ELEMENT2: [
    { ID: 909, NAME: 'ELEMENT2', DETAILS: 'OUTAGE' },
    { ID: 910, NAME: 'ELEMENT2', DETAILS: 'OUTAGE' },
  ],
  ELEMENT1: [
    { ID: 1110, NAME: 'WORK_PACKAGE', DETAILS: 'INLINE' },
    { ID: 1111, NAME: 'WORK_PACKAGE', DETAILS: 'INLINE' },
    { ID: 1112, NAME: 'WORK_PACKAGE', DETAILS: 'INLINE' },
    { ID: 1113, NAME: 'WORK_PACKAGE', DETAILS: 'INLINE' },
  ],
}

const result = {}

for (let key in var2) {
  result[key] = var2[key].filter(o => var1[key]?.includes(o.ID))
}

console.log(JSON.stringify(result, null, 2))

標籤：javascript ecmascript-6

上一篇：僅當陣列元素包含錯誤時才合并兩個物件陣列

下一篇：如何在頁眉和頁腳之間放置一個固定的div