目標是xticklabel在繪圖時修改pcolormesh和scatter。
但是,我無法訪問現有的 xtick 標簽。
簡單地
ax = plt.axes()
labels_x = [item.get_text() for item in ax.get_xticklabels()]
產生了:
['', '', '', '', '', '']
或者
fig.canvas.draw()
xticks = ax.get_xticklabels()
產生了:
['', '', '', '', '', '']
不回傳相應的標簽。
我可以知道如何正確訪問plt案例的軸刻度標簽嗎?
為了可讀性,我將代碼分成兩部分。
- 第一部分生成用于繪圖的資料
- 第二部分處理繪圖
第 1 部分:生成用于繪圖的資料
import matplotlib.pyplot as plt
import numpy as np
import pandas as pd
import math
np.random.seed(0)
increment=120
max_val=172800
aran=np.arange(0,max_val,increment).astype(int)
arr=np.concatenate((aran.reshape(-1,1), np.random.random((aran.shape[0],4))), axis=1)
df=pd.DataFrame(arr,columns=[('lapse',''),('a','i'),('a','j'),('b','k'),('c','')])
ridx=df.index[df[('lapse','')] == 3600].tolist()[0] 1 # minus 1 so to allow 3600 start at new row
df[('event','')]=0
df.loc[[1,2,3,10,20,30],[('event','')]]=1
arr=df[[('a','i'),('event','')]].to_numpy()
col_len=ridx
v=arr[:,0].view()
nrow_size=math.ceil(v.shape[0]/col_len)
X=np.pad(arr[:,0].astype(float), (0, nrow_size*col_len - arr[:,0].size),
mode='constant', constant_values=np.nan).reshape(nrow_size,col_len)
mask_append_val=0 # This value must equal to 1 for masking
arrshape=np.pad(arr[:,1].astype(float), (0, nrow_size*col_len - arr[:,1].size),
mode='constant', constant_values=mask_append_val).reshape(nrow_size,col_len)
第 2 節繪圖
fig = plt.figure(figsize=(8,6))
plt.pcolormesh(X,cmap="plasma")
x,y = X.shape
xs,ys = np.ogrid[:x,:y]
# the non-zero coordinates
u = np.argwhere(arrshape)
plt.scatter(ys[:,u[:,1]].ravel() .5,xs[u[:,0]].ravel() 0.5,marker='*', color='r', s=55)
plt.gca().invert_yaxis()
xlabels_to_use_this=df.loc[:30,[('lapse','')]].values.tolist()
# ax = plt.axes()
# labels_x = [item.get_text() for item in ax.get_xticklabels()]
# labels_y = [item.get_text() for item in ax.get_yticklabels()]
plt.xlabel('X-axis')
plt.ylabel('Y-axis')
plt.title("Plot 2D array")
plt.colorbar()
plt.tight_layout()
plt.show()
預期輸出

uj5u.com熱心網友回復:
這就是使用 matplotlibpcolormesh和生成圖的方式scatter:
import matplotlib.pyplot as plt
from matplotlib.ticker import MultipleLocator
import pandas as pd
import numpy as np
np.random.seed(0)
increment = 120
max_val = 172800
aran = np.arange(0, max_val, increment).astype(int)
arr_df = np.concatenate((aran.reshape(-1, 1), np.random.random((aran.shape[0], 4))), axis=1)
df = pd.DataFrame(arr_df, columns=[('lapse', ''), ('a', 'i'), ('a', 'j'), ('b', 'k'), ('c', '')])
df[('event', '')] = 0
df.loc[[1, 2, 3, 10, 20, 30], [('event', '')]] = 1
col_len_lapse = 3600
col_len = df[df[('lapse', '')] == col_len_lapse].index[0]
nrow_size = int(np.ceil(v.shape[0] / col_len))
a_i_values = df[('a', 'i')].values
a_i_values_meshed = np.pad(a_i_values.astype(float), (0, nrow_size * col_len - len(a_i_values)),
mode='constant', constant_values=np.nan).reshape(nrow_size, col_len)
fig, ax = plt.subplots(figsize=(8, 6))
# the x_values indicate the mesh borders, subtract one half so the ticks can be at the centers
x_values = df[('lapse', '')][:col_len 1].values - increment / 2
# divide lapses for y by col_len_lapse to get hours
y_values = df[('lapse', '')][::col_len].values / col_len_lapse - 0.5
y_values = np.append(y_values, 2 * y_values[-1] - y_values[-2]) # add the bottommost border (linear extension)
mesh = ax.pcolormesh(x_values, y_values, a_i_values_meshed, cmap="plasma")
event_lapses = df[('lapse', '')][df[('event', '')] == 1]
ax.scatter(event_lapses % col_len_lapse,
np.floor(event_lapses / col_len_lapse),
marker='*', color='red', edgecolor='white', s=55)
ax.xaxis.set_major_locator(MultipleLocator(increment * 5))
ax.yaxis.set_major_locator(MultipleLocator(5))
ax.invert_yaxis()
ax.set_xlabel('X-axis (s)')
ax.set_ylabel('Y-axis (hours)')
ax.set_title("Plot 2D array")
plt.colorbar(mesh)
plt.tight_layout() # fit the labels nicely into the plot
plt.show()

使用 Seaborn 可以簡化事情,添加新的小時和秒列,并使用 pandas' pivot(它會自動用NaNs填充不可用的資料)。添加xtick_labels=5每 5 個位置設定標簽。(星星為lapse=36001 小時 0 秒)。
import matplotlib.pyplot as plt
import seaborn as sns
import pandas as pd
import numpy as np
# df created as before
df['hours'] = (df[('lapse', '')].astype(int) // 3600)
df['seconds'] = (df[('lapse', '')].astype(int) % 3600)
df_heatmap = df.pivot(index='hours', columns='seconds', values=('a', 'i'))
df_heatmap_markers = df.pivot(index='hours', columns='seconds', values=('event', '')).replace(
{0: '', 1: '★', np.nan: ''})
fig, ax = plt.subplots(figsize=(8, 6))
sns.heatmap(df_heatmap, xticklabels=5, yticklabels=5,
annot=df_heatmap_markers, fmt='s', annot_kws={'color': 'lime'}, ax=ax)
ax.tick_params(rotation=0)
plt.tight_layout()
plt.show()

PS:代替“秒”列,“分鐘”列也可能很有趣。
uj5u.com熱心網友回復:
我最終使用 Seaborn 來解決這個問題。
具體來說,以下幾行可以輕松調整 xticklabel
fig.canvas.draw()
new_ticks = [i.get_text() for i in g.get_xticklabels()]
i=[int(idx) for idx in new_ticks]
newlabel=xlabels_to_use_this[i]
newlabel=[np.array2string(x, precision=0) for x in newlabel]
繪圖的完整代碼如下
import seaborn as sns
fig, ax = plt.subplots()
sns.heatmap(X,ax=ax)
x,y = X.shape
xs,ys = np.ogrid[:x,:y]
# the non-zero coordinates
u = np.argwhere(arrshape)
g=sns.scatterplot(ys[:,u[:,1]].ravel() .5,xs[u[:,0]].ravel() 0.5,marker='*', color='r', s=55)
fig.canvas.draw()
new_ticks = [i.get_text() for i in g.get_xticklabels()]
i=[int(idx) for idx in new_ticks]
newlabel=xlabels_to_use_this[i]
newlabel=[np.array2string(x, precision=0) for x in newlabel]
ax.set_xticklabels(newlabel)
ax.set_xticklabels(ax.get_xticklabels(),rotation = 90)
for ind, label in enumerate(g.get_xticklabels()):
if ind % 2 == 0: # every 10th label is kept
label.set_visible(True)
else:
label.set_visible(False)
for ind, label in enumerate(g.get_yticklabels()):
if ind % 4 == 0: # every 10th label is kept
label.set_visible(True)
else:
label.set_visible(False)
plt.xlabel('Elapsed (s)')
plt.ylabel('Hour (h)')
plt.title("Rastar Plot")
plt.tight_layout()
plt.show()

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標籤:Python matplotlib
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